/export/starexec/sandbox2/solver/bin/starexec_run_tct_dc /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(?,O(n^2)) * Step 1: NaturalMI. WORST_CASE(?,O(n^2)) + Considered Problem: - Strict TRS: bits(0()) -> 0() bits(s(x)) -> s(bits(half(s(x)))) half(0()) -> 0() half(s(0())) -> 0() half(s(s(x))) -> s(half(x)) - Signature: {bits/1,half/1} / {0/0,s/1} - Obligation: derivational complexity wrt. signature {0,bits,half,s} + Applied Processor: NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = NoUArgs, urules = NoURules, selector = Just any strict-rules} + Details: We apply a matrix interpretation of kind triangular matrix interpretation: Following symbols are considered usable: all TcT has computed the following interpretation: p(0) = [1] p(bits) = [1] x1 + [2] p(half) = [1] x1 + [0] p(s) = [1] x1 + [0] Following rules are strictly oriented: bits(0()) = [3] > [1] = 0() Following rules are (at-least) weakly oriented: bits(s(x)) = [1] x + [2] >= [1] x + [2] = s(bits(half(s(x)))) half(0()) = [1] >= [1] = 0() half(s(0())) = [1] >= [1] = 0() half(s(s(x))) = [1] x + [0] >= [1] x + [0] = s(half(x)) * Step 2: WeightGap. WORST_CASE(?,O(n^2)) + Considered Problem: - Strict TRS: bits(s(x)) -> s(bits(half(s(x)))) half(0()) -> 0() half(s(0())) -> 0() half(s(s(x))) -> s(half(x)) - Weak TRS: bits(0()) -> 0() - Signature: {bits/1,half/1} / {0/0,s/1} - Obligation: derivational complexity wrt. signature {0,bits,half,s} + Applied Processor: WeightGap {wgDimension = 1, wgDegree = 1, wgKind = Algebraic, wgUArgs = NoUArgs, wgOn = WgOnAny} + Details: The weightgap principle applies using the following nonconstant growth matrix-interpretation: We apply a matrix interpretation of kind triangular matrix interpretation: Following symbols are considered usable: all TcT has computed the following interpretation: p(0) = [0] p(bits) = [1] x1 + [0] p(half) = [1] x1 + [13] p(s) = [1] x1 + [1] Following rules are strictly oriented: half(0()) = [13] > [0] = 0() half(s(0())) = [14] > [0] = 0() half(s(s(x))) = [1] x + [15] > [1] x + [14] = s(half(x)) Following rules are (at-least) weakly oriented: bits(0()) = [0] >= [0] = 0() bits(s(x)) = [1] x + [1] >= [1] x + [15] = s(bits(half(s(x)))) Further, it can be verified that all rules not oriented are covered by the weightgap condition. * Step 3: MI. WORST_CASE(?,O(n^2)) + Considered Problem: - Strict TRS: bits(s(x)) -> s(bits(half(s(x)))) - Weak TRS: bits(0()) -> 0() half(0()) -> 0() half(s(0())) -> 0() half(s(s(x))) -> s(half(x)) - Signature: {bits/1,half/1} / {0/0,s/1} - Obligation: derivational complexity wrt. signature {0,bits,half,s} + Applied Processor: MI {miKind = Automaton (Just 2), miDimension = 3, miUArgs = NoUArgs, miURules = NoURules, miSelector = Just any strict-rules} + Details: We apply a matrix interpretation of kind Automaton (Just 2): Following symbols are considered usable: all TcT has computed the following interpretation: p(0) = [0] [0] [0] p(bits) = [1 0 4] [4] [0 0 1] x_1 + [3] [0 0 1] [4] p(half) = [1 0 0] [0] [0 1 0] x_1 + [0] [0 1 0] [0] p(s) = [1 0 0] [1] [0 1 0] x_1 + [1] [0 1 0] [2] Following rules are strictly oriented: bits(s(x)) = [1 4 0] [13] [0 1 0] x + [5] [0 1 0] [6] > [1 4 0] [10] [0 1 0] x + [5] [0 1 0] [6] = s(bits(half(s(x)))) Following rules are (at-least) weakly oriented: bits(0()) = [4] [3] [4] >= [0] [0] [0] = 0() half(0()) = [0] [0] [0] >= [0] [0] [0] = 0() half(s(0())) = [1] [1] [1] >= [0] [0] [0] = 0() half(s(s(x))) = [1 0 0] [2] [0 1 0] x + [2] [0 1 0] [2] >= [1 0 0] [1] [0 1 0] x + [1] [0 1 0] [2] = s(half(x)) * Step 4: EmptyProcessor. WORST_CASE(?,O(1)) + Considered Problem: - Weak TRS: bits(0()) -> 0() bits(s(x)) -> s(bits(half(s(x)))) half(0()) -> 0() half(s(0())) -> 0() half(s(s(x))) -> s(half(x)) - Signature: {bits/1,half/1} / {0/0,s/1} - Obligation: derivational complexity wrt. signature {0,bits,half,s} + Applied Processor: EmptyProcessor + Details: The problem is already closed. The intended complexity is O(1). WORST_CASE(?,O(n^2))