/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). (0) CpxTRS (1) CpxTrsToCdtProof [UPPER BOUND(ID), 4 ms] (2) CdtProblem (3) CdtUsableRulesProof [BOTH BOUNDS(ID, ID), 0 ms] (4) CdtProblem (5) CdtRuleRemovalProof [UPPER BOUND(ADD(n^1)), 33 ms] (6) CdtProblem (7) SIsEmptyProof [BOTH BOUNDS(ID, ID), 0 ms] (8) BOUNDS(1, 1) (9) RenamingProof [BOTH BOUNDS(ID, ID), 0 ms] (10) CpxTRS (11) SlicingProof [LOWER BOUND(ID), 0 ms] (12) CpxTRS (13) TypeInferenceProof [BOTH BOUNDS(ID, ID), 0 ms] (14) typed CpxTrs (15) OrderProof [LOWER BOUND(ID), 0 ms] (16) typed CpxTrs (17) RewriteLemmaProof [LOWER BOUND(ID), 519 ms] (18) proven lower bound (19) LowerBoundPropagationProof [FINISHED, 0 ms] (20) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). The TRS R consists of the following rules: *(x, +(y, z)) -> +(*(x, y), *(x, z)) S is empty. Rewrite Strategy: INNERMOST ---------------------------------------- (1) CpxTrsToCdtProof (UPPER BOUND(ID)) Converted Cpx (relative) TRS to CDT ---------------------------------------- (2) Obligation: Complexity Dependency Tuples Problem Rules: *(z0, +(z1, z2)) -> +(*(z0, z1), *(z0, z2)) Tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) S tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) K tuples:none Defined Rule Symbols: *_2 Defined Pair Symbols: *'_2 Compound Symbols: c_2 ---------------------------------------- (3) CdtUsableRulesProof (BOTH BOUNDS(ID, ID)) The following rules are not usable and were removed: *(z0, +(z1, z2)) -> +(*(z0, z1), *(z0, z2)) ---------------------------------------- (4) Obligation: Complexity Dependency Tuples Problem Rules:none Tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) S tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) K tuples:none Defined Rule Symbols:none Defined Pair Symbols: *'_2 Compound Symbols: c_2 ---------------------------------------- (5) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1))) Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S. *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) We considered the (Usable) Rules:none And the Tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) The order we found is given by the following interpretation: Polynomial interpretation : POL(*'(x_1, x_2)) = [2]x_2 POL(+(x_1, x_2)) = [3] + x_1 + x_2 POL(c(x_1, x_2)) = x_1 + x_2 ---------------------------------------- (6) Obligation: Complexity Dependency Tuples Problem Rules:none Tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) S tuples:none K tuples: *'(z0, +(z1, z2)) -> c(*'(z0, z1), *'(z0, z2)) Defined Rule Symbols:none Defined Pair Symbols: *'_2 Compound Symbols: c_2 ---------------------------------------- (7) SIsEmptyProof (BOTH BOUNDS(ID, ID)) The set S is empty ---------------------------------------- (8) BOUNDS(1, 1) ---------------------------------------- (9) RenamingProof (BOTH BOUNDS(ID, ID)) Renamed function symbols to avoid clashes with predefined symbol. ---------------------------------------- (10) Obligation: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: *'(x, +'(y, z)) -> +'(*'(x, y), *'(x, z)) S is empty. Rewrite Strategy: INNERMOST ---------------------------------------- (11) SlicingProof (LOWER BOUND(ID)) Sliced the following arguments: *'/0 ---------------------------------------- (12) Obligation: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: *'(+'(y, z)) -> +'(*'(y), *'(z)) S is empty. Rewrite Strategy: INNERMOST ---------------------------------------- (13) TypeInferenceProof (BOTH BOUNDS(ID, ID)) Infered types. ---------------------------------------- (14) Obligation: Innermost TRS: Rules: *'(+'(y, z)) -> +'(*'(y), *'(z)) Types: *' :: +' -> +' +' :: +' -> +' -> +' hole_+'1_0 :: +' gen_+'2_0 :: Nat -> +' ---------------------------------------- (15) OrderProof (LOWER BOUND(ID)) Heuristically decided to analyse the following defined symbols: *' ---------------------------------------- (16) Obligation: Innermost TRS: Rules: *'(+'(y, z)) -> +'(*'(y), *'(z)) Types: *' :: +' -> +' +' :: +' -> +' -> +' hole_+'1_0 :: +' gen_+'2_0 :: Nat -> +' Generator Equations: gen_+'2_0(0) <=> hole_+'1_0 gen_+'2_0(+(x, 1)) <=> +'(hole_+'1_0, gen_+'2_0(x)) The following defined symbols remain to be analysed: *' ---------------------------------------- (17) RewriteLemmaProof (LOWER BOUND(ID)) Proved the following rewrite lemma: *'(gen_+'2_0(+(1, n4_0))) -> *3_0, rt in Omega(n4_0) Induction Base: *'(gen_+'2_0(+(1, 0))) Induction Step: *'(gen_+'2_0(+(1, +(n4_0, 1)))) ->_R^Omega(1) +'(*'(hole_+'1_0), *'(gen_+'2_0(+(1, n4_0)))) ->_IH +'(*'(hole_+'1_0), *3_0) We have rt in Omega(n^1) and sz in O(n). Thus, we have irc_R in Omega(n). ---------------------------------------- (18) Obligation: Proved the lower bound n^1 for the following obligation: Innermost TRS: Rules: *'(+'(y, z)) -> +'(*'(y), *'(z)) Types: *' :: +' -> +' +' :: +' -> +' -> +' hole_+'1_0 :: +' gen_+'2_0 :: Nat -> +' Generator Equations: gen_+'2_0(0) <=> hole_+'1_0 gen_+'2_0(+(x, 1)) <=> +'(hole_+'1_0, gen_+'2_0(x)) The following defined symbols remain to be analysed: *' ---------------------------------------- (19) LowerBoundPropagationProof (FINISHED) Propagated lower bound. ---------------------------------------- (20) BOUNDS(n^1, INF)