/export/starexec/sandbox/solver/bin/starexec_run_tct_rc /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1),?) * Step 1: Sum. WORST_CASE(Omega(n^1),?) + Considered Problem: - Strict TRS: if_quot(false(),x,y) -> 0() if_quot(true(),x,y) -> s(quot(minus(x,y),y)) le(0(),y) -> true() le(s(x),0()) -> false() le(s(x),s(y)) -> le(x,y) minus(x,0()) -> x minus(s(x),s(y)) -> minus(x,y) quot(x,s(y)) -> if_quot(le(s(y),x),x,s(y)) - Signature: {if_quot/3,le/2,minus/2,quot/2} / {0/0,false/0,s/1,true/0} - Obligation: runtime complexity wrt. defined symbols {if_quot,le,minus,quot} and constructors {0,false,s,true} + Applied Processor: Sum {left = someStrategy, right = someStrategy} + Details: () * Step 2: Sum. WORST_CASE(Omega(n^1),?) + Considered Problem: - Strict TRS: if_quot(false(),x,y) -> 0() if_quot(true(),x,y) -> s(quot(minus(x,y),y)) le(0(),y) -> true() le(s(x),0()) -> false() le(s(x),s(y)) -> le(x,y) minus(x,0()) -> x minus(s(x),s(y)) -> minus(x,y) quot(x,s(y)) -> if_quot(le(s(y),x),x,s(y)) - Signature: {if_quot/3,le/2,minus/2,quot/2} / {0/0,false/0,s/1,true/0} - Obligation: runtime complexity wrt. defined symbols {if_quot,le,minus,quot} and constructors {0,false,s,true} + Applied Processor: Sum {left = someStrategy, right = someStrategy} + Details: () * Step 3: DecreasingLoops. WORST_CASE(Omega(n^1),?) + Considered Problem: - Strict TRS: if_quot(false(),x,y) -> 0() if_quot(true(),x,y) -> s(quot(minus(x,y),y)) le(0(),y) -> true() le(s(x),0()) -> false() le(s(x),s(y)) -> le(x,y) minus(x,0()) -> x minus(s(x),s(y)) -> minus(x,y) quot(x,s(y)) -> if_quot(le(s(y),x),x,s(y)) - Signature: {if_quot/3,le/2,minus/2,quot/2} / {0/0,false/0,s/1,true/0} - Obligation: runtime complexity wrt. defined symbols {if_quot,le,minus,quot} and constructors {0,false,s,true} + Applied Processor: DecreasingLoops {bound = AnyLoop, narrow = 10} + Details: The system has following decreasing Loops: le(x,y){x -> s(x),y -> s(y)} = le(s(x),s(y)) ->^+ le(x,y) = C[le(x,y) = le(x,y){}] WORST_CASE(Omega(n^1),?)