/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). (0) CpxTRS (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] (2) TRS for Loop Detection (3) DecreasingLoopProof [FINISHED, 0 ms] (4) BOUNDS(EXP, INF) ---------------------------------------- (0) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). The TRS R consists of the following rules: le(0, y) -> true le(s(x), 0) -> false le(s(x), s(y)) -> le(x, y) eq(0, 0) -> true eq(0, s(y)) -> false eq(s(x), 0) -> false eq(s(x), s(y)) -> eq(x, y) if(true, x, y) -> x if(false, x, y) -> y minsort(nil) -> nil minsort(cons(x, y)) -> cons(min(x, y), minsort(del(min(x, y), cons(x, y)))) min(x, nil) -> x min(x, cons(y, z)) -> if(le(x, y), min(x, z), min(y, z)) del(x, nil) -> nil del(x, cons(y, z)) -> if(eq(x, y), z, cons(y, del(x, z))) S is empty. Rewrite Strategy: FULL ---------------------------------------- (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) Transformed a relative TRS into a decreasing-loop problem. ---------------------------------------- (2) Obligation: Analyzing the following TRS for decreasing loops: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). The TRS R consists of the following rules: le(0, y) -> true le(s(x), 0) -> false le(s(x), s(y)) -> le(x, y) eq(0, 0) -> true eq(0, s(y)) -> false eq(s(x), 0) -> false eq(s(x), s(y)) -> eq(x, y) if(true, x, y) -> x if(false, x, y) -> y minsort(nil) -> nil minsort(cons(x, y)) -> cons(min(x, y), minsort(del(min(x, y), cons(x, y)))) min(x, nil) -> x min(x, cons(y, z)) -> if(le(x, y), min(x, z), min(y, z)) del(x, nil) -> nil del(x, cons(y, z)) -> if(eq(x, y), z, cons(y, del(x, z))) S is empty. Rewrite Strategy: FULL ---------------------------------------- (3) DecreasingLoopProof (FINISHED) The following loop(s) give(s) rise to the lower bound EXP: The rewrite sequence min(x, cons(y, z)) ->^+ if(le(x, y), min(x, z), min(y, z)) gives rise to a decreasing loop by considering the right hand sides subterm at position [1]. The pumping substitution is [z / cons(y, z)]. The result substitution is [ ]. The rewrite sequence min(x, cons(y, z)) ->^+ if(le(x, y), min(x, z), min(y, z)) gives rise to a decreasing loop by considering the right hand sides subterm at position [2]. The pumping substitution is [z / cons(y, z)]. The result substitution is [x / y]. ---------------------------------------- (4) BOUNDS(EXP, INF)