/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). (0) CpxTRS (1) RenamingProof [BOTH BOUNDS(ID, ID), 0 ms] (2) CpxTRS (3) TypeInferenceProof [BOTH BOUNDS(ID, ID), 0 ms] (4) typed CpxTrs (5) OrderProof [LOWER BOUND(ID), 0 ms] (6) typed CpxTrs (7) RewriteLemmaProof [LOWER BOUND(ID), 271 ms] (8) BEST (9) proven lower bound (10) LowerBoundPropagationProof [FINISHED, 0 ms] (11) BOUNDS(n^1, INF) (12) typed CpxTrs (13) RewriteLemmaProof [LOWER BOUND(ID), 46 ms] (14) typed CpxTrs (15) RewriteLemmaProof [LOWER BOUND(ID), 156 ms] (16) typed CpxTrs ---------------------------------------- (0) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) S is empty. Rewrite Strategy: FULL ---------------------------------------- (1) RenamingProof (BOTH BOUNDS(ID, ID)) Renamed function symbols to avoid clashes with predefined symbol. ---------------------------------------- (2) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) S is empty. Rewrite Strategy: FULL ---------------------------------------- (3) TypeInferenceProof (BOTH BOUNDS(ID, ID)) Infered types. ---------------------------------------- (4) Obligation: TRS: Rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) Types: top :: free:serve -> top free :: free:serve -> free:serve check :: free:serve -> free:serve new :: free:serve -> free:serve old :: free:serve -> free:serve serve :: free:serve hole_top1_0 :: top hole_free:serve2_0 :: free:serve gen_free:serve3_0 :: Nat -> free:serve ---------------------------------------- (5) OrderProof (LOWER BOUND(ID)) Heuristically decided to analyse the following defined symbols: top, check, new, old They will be analysed ascendingly in the following order: check < top new < top new < check old < check ---------------------------------------- (6) Obligation: TRS: Rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) Types: top :: free:serve -> top free :: free:serve -> free:serve check :: free:serve -> free:serve new :: free:serve -> free:serve old :: free:serve -> free:serve serve :: free:serve hole_top1_0 :: top hole_free:serve2_0 :: free:serve gen_free:serve3_0 :: Nat -> free:serve Generator Equations: gen_free:serve3_0(0) <=> serve gen_free:serve3_0(+(x, 1)) <=> free(gen_free:serve3_0(x)) The following defined symbols remain to be analysed: new, top, check, old They will be analysed ascendingly in the following order: check < top new < top new < check old < check ---------------------------------------- (7) RewriteLemmaProof (LOWER BOUND(ID)) Proved the following rewrite lemma: new(gen_free:serve3_0(n5_0)) -> gen_free:serve3_0(+(1, n5_0)), rt in Omega(1 + n5_0) Induction Base: new(gen_free:serve3_0(0)) ->_R^Omega(1) free(serve) Induction Step: new(gen_free:serve3_0(+(n5_0, 1))) ->_R^Omega(1) free(new(gen_free:serve3_0(n5_0))) ->_IH free(gen_free:serve3_0(+(1, c6_0))) We have rt in Omega(n^1) and sz in O(n). Thus, we have irc_R in Omega(n). ---------------------------------------- (8) Complex Obligation (BEST) ---------------------------------------- (9) Obligation: Proved the lower bound n^1 for the following obligation: TRS: Rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) Types: top :: free:serve -> top free :: free:serve -> free:serve check :: free:serve -> free:serve new :: free:serve -> free:serve old :: free:serve -> free:serve serve :: free:serve hole_top1_0 :: top hole_free:serve2_0 :: free:serve gen_free:serve3_0 :: Nat -> free:serve Generator Equations: gen_free:serve3_0(0) <=> serve gen_free:serve3_0(+(x, 1)) <=> free(gen_free:serve3_0(x)) The following defined symbols remain to be analysed: new, top, check, old They will be analysed ascendingly in the following order: check < top new < top new < check old < check ---------------------------------------- (10) LowerBoundPropagationProof (FINISHED) Propagated lower bound. ---------------------------------------- (11) BOUNDS(n^1, INF) ---------------------------------------- (12) Obligation: TRS: Rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) Types: top :: free:serve -> top free :: free:serve -> free:serve check :: free:serve -> free:serve new :: free:serve -> free:serve old :: free:serve -> free:serve serve :: free:serve hole_top1_0 :: top hole_free:serve2_0 :: free:serve gen_free:serve3_0 :: Nat -> free:serve Lemmas: new(gen_free:serve3_0(n5_0)) -> gen_free:serve3_0(+(1, n5_0)), rt in Omega(1 + n5_0) Generator Equations: gen_free:serve3_0(0) <=> serve gen_free:serve3_0(+(x, 1)) <=> free(gen_free:serve3_0(x)) The following defined symbols remain to be analysed: old, top, check They will be analysed ascendingly in the following order: check < top old < check ---------------------------------------- (13) RewriteLemmaProof (LOWER BOUND(ID)) Proved the following rewrite lemma: old(gen_free:serve3_0(n194_0)) -> gen_free:serve3_0(+(1, n194_0)), rt in Omega(1 + n194_0) Induction Base: old(gen_free:serve3_0(0)) ->_R^Omega(1) free(serve) Induction Step: old(gen_free:serve3_0(+(n194_0, 1))) ->_R^Omega(1) free(old(gen_free:serve3_0(n194_0))) ->_IH free(gen_free:serve3_0(+(1, c195_0))) We have rt in Omega(n^1) and sz in O(n). Thus, we have irc_R in Omega(n). ---------------------------------------- (14) Obligation: TRS: Rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) Types: top :: free:serve -> top free :: free:serve -> free:serve check :: free:serve -> free:serve new :: free:serve -> free:serve old :: free:serve -> free:serve serve :: free:serve hole_top1_0 :: top hole_free:serve2_0 :: free:serve gen_free:serve3_0 :: Nat -> free:serve Lemmas: new(gen_free:serve3_0(n5_0)) -> gen_free:serve3_0(+(1, n5_0)), rt in Omega(1 + n5_0) old(gen_free:serve3_0(n194_0)) -> gen_free:serve3_0(+(1, n194_0)), rt in Omega(1 + n194_0) Generator Equations: gen_free:serve3_0(0) <=> serve gen_free:serve3_0(+(x, 1)) <=> free(gen_free:serve3_0(x)) The following defined symbols remain to be analysed: check, top They will be analysed ascendingly in the following order: check < top ---------------------------------------- (15) RewriteLemmaProof (LOWER BOUND(ID)) Proved the following rewrite lemma: check(gen_free:serve3_0(+(1, n387_0))) -> *4_0, rt in Omega(n387_0) Induction Base: check(gen_free:serve3_0(+(1, 0))) Induction Step: check(gen_free:serve3_0(+(1, +(n387_0, 1)))) ->_R^Omega(1) free(check(gen_free:serve3_0(+(1, n387_0)))) ->_IH free(*4_0) We have rt in Omega(n^1) and sz in O(n). Thus, we have irc_R in Omega(n). ---------------------------------------- (16) Obligation: TRS: Rules: top(free(x)) -> top(check(new(x))) new(free(x)) -> free(new(x)) old(free(x)) -> free(old(x)) new(serve) -> free(serve) old(serve) -> free(serve) check(free(x)) -> free(check(x)) check(new(x)) -> new(check(x)) check(old(x)) -> old(check(x)) check(old(x)) -> old(x) Types: top :: free:serve -> top free :: free:serve -> free:serve check :: free:serve -> free:serve new :: free:serve -> free:serve old :: free:serve -> free:serve serve :: free:serve hole_top1_0 :: top hole_free:serve2_0 :: free:serve gen_free:serve3_0 :: Nat -> free:serve Lemmas: new(gen_free:serve3_0(n5_0)) -> gen_free:serve3_0(+(1, n5_0)), rt in Omega(1 + n5_0) old(gen_free:serve3_0(n194_0)) -> gen_free:serve3_0(+(1, n194_0)), rt in Omega(1 + n194_0) check(gen_free:serve3_0(+(1, n387_0))) -> *4_0, rt in Omega(n387_0) Generator Equations: gen_free:serve3_0(0) <=> serve gen_free:serve3_0(+(x, 1)) <=> free(gen_free:serve3_0(x)) The following defined symbols remain to be analysed: top