/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Quasi decreasingness of the given CTRS could be proven: (0) CTRS (1) CTRSToQTRSProof [SOUND, 0 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 60 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Conditional term rewrite system: The TRS R consists of the following rules: g(s(x)) -> x h(s(x)) -> x The conditional TRS C consists of the following conditional rules: f(x, y) -> g(s(x)) <= c(g(x)) -> c(a) f(x, y) -> h(s(x)) <= c(h(x)) -> c(a) ---------------------------------------- (1) CTRSToQTRSProof (SOUND) The conditional rules have been transormed into unconditional rules according to [CTRS,AAECCNOC]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(x, y) -> U1(c(g(x)), x) U1(c(a), x) -> g(s(x)) f(x, y) -> U2(c(h(x)), x) U2(c(a), x) -> h(s(x)) g(s(x)) -> x h(s(x)) -> x Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(U1(x_1, x_2)) = x_1 + x_2 POL(U2(x_1, x_2)) = x_1 + x_2 POL(a) = 0 POL(c(x_1)) = x_1 POL(f(x_1, x_2)) = 1 + 2*x_1 + x_2 POL(g(x_1)) = x_1 POL(h(x_1)) = x_1 POL(s(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(x, y) -> U1(c(g(x)), x) f(x, y) -> U2(c(h(x)), x) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: U1(c(a), x) -> g(s(x)) U2(c(a), x) -> h(s(x)) g(s(x)) -> x h(s(x)) -> x Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Knuth-Bendix order [KBO] with precedence:h_1 > s_1 > U2_2 > g_1 > a > U1_2 > c_1 and weight map: a=1 c_1=1 g_1=1 s_1=1 h_1=1 U1_2=1 U2_2=1 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: U1(c(a), x) -> g(s(x)) U2(c(a), x) -> h(s(x)) g(s(x)) -> x h(s(x)) -> x ---------------------------------------- (6) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (7) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (8) YES