/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x:S y:S) (RULES a -> c a -> d b -> c b -> d c -> e d -> e f(x:S) -> pair(x:S,y:S) | s(x:S) ->* t(y:S) g(x:S,x:S) -> h(x:S,x:S) k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) ) Problem 1: Valid CTRS Processor: -> Rules: a -> c a -> d b -> c b -> d c -> e d -> e f(x:S) -> pair(x:S,y:S) | s(x:S) ->* t(y:S) g(x:S,x:S) -> h(x:S,x:S) k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: A -> C A -> D B -> C B -> D S(c) -> K S(c) -> L -> QPairs: Empty -> Rules: a -> c a -> d b -> c b -> d c -> e d -> e f(x:S) -> pair(x:S,y:S) | s(x:S) ->* t(y:S) g(x:S,x:S) -> h(x:S,x:S) k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) Conditional Termination Problem 2: -> Pairs: F(x:S) -> S(x:S) -> QPairs: S(c) -> K S(c) -> L -> Rules: a -> c a -> d b -> c b -> d c -> e d -> e f(x:S) -> pair(x:S,y:S) | s(x:S) ->* t(y:S) g(x:S,x:S) -> h(x:S,x:S) k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) The problem is decomposed in 2 subproblems. Problem 1.1: SCC Processor: -> Pairs: A -> C A -> D B -> C B -> D S(c) -> K S(c) -> L -> QPairs: Empty -> Rules: a -> c a -> d b -> c b -> d c -> e d -> e f(x:S) -> pair(x:S,y:S) | s(x:S) ->* t(y:S) g(x:S,x:S) -> h(x:S,x:S) k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: SCC Processor: -> Pairs: F(x:S) -> S(x:S) -> QPairs: S(c) -> K S(c) -> L -> Rules: a -> c a -> d b -> c b -> d c -> e d -> e f(x:S) -> pair(x:S,y:S) | s(x:S) ->* t(y:S) g(x:S,x:S) -> h(x:S,x:S) k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) ->Strongly Connected Components: There is no strongly connected component The problem is finite.