/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Quasi decreasingness of the given CTRS could be proven: (0) CTRS (1) CTRSToQTRSProof [SOUND, 0 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 53 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) QTRSRRRProof [EQUIVALENT, 5 ms] (8) QTRS (9) QTRSRRRProof [EQUIVALENT, 0 ms] (10) QTRS (11) QTRSRRRProof [EQUIVALENT, 0 ms] (12) QTRS (13) RisEmptyProof [EQUIVALENT, 0 ms] (14) YES ---------------------------------------- (0) Obligation: Conditional term rewrite system: The TRS R consists of the following rules: a -> c a -> d b -> c b -> d c -> e d -> e k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) g(x, x) -> h(x, x) The conditional TRS C consists of the following conditional rules: f(x) -> pair(x, y) <= s(x) -> t(y) ---------------------------------------- (1) CTRSToQTRSProof (SOUND) The conditional rules have been transormed into unconditional rules according to [CTRS,AAECCNOC]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(x) -> U1(s(x), x) U1(t(y), x) -> pair(x, y) a -> c a -> d b -> c b -> d c -> e d -> e k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) g(x, x) -> h(x, x) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(U1(x_1, x_2)) = 2 + x_1 + x_2 POL(a) = 2 POL(b) = 1 POL(c) = 0 POL(d) = 1 POL(e) = 0 POL(f(x_1)) = 2 + 2*x_1 POL(g(x_1, x_2)) = 1 + x_1 + 2*x_2 POL(h(x_1, x_2)) = 1 + x_1 + x_2 POL(k) = 0 POL(l) = 0 POL(pair(x_1, x_2)) = 2 + x_1 + x_2 POL(s(x_1)) = x_1 POL(t(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: a -> c a -> d b -> c d -> e ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(x) -> U1(s(x), x) U1(t(y), x) -> pair(x, y) b -> d c -> e k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) g(x, x) -> h(x, x) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(U1(x_1, x_2)) = 2 + x_1 + x_2 POL(b) = 1 POL(c) = 0 POL(d) = 0 POL(e) = 0 POL(f(x_1)) = 2 + 2*x_1 POL(g(x_1, x_2)) = 2 + x_1 + 2*x_2 POL(h(x_1, x_2)) = 2 + x_1 + x_2 POL(k) = 0 POL(l) = 0 POL(pair(x_1, x_2)) = 2 + x_1 + x_2 POL(s(x_1)) = x_1 POL(t(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: b -> d ---------------------------------------- (6) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(x) -> U1(s(x), x) U1(t(y), x) -> pair(x, y) c -> e k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) g(x, x) -> h(x, x) Q is empty. ---------------------------------------- (7) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(U1(x_1, x_2)) = 2 + x_1 + x_2 POL(c) = 0 POL(e) = 0 POL(f(x_1)) = 2 + 2*x_1 POL(g(x_1, x_2)) = 1 + x_1 + 2*x_2 POL(h(x_1, x_2)) = x_1 + x_2 POL(k) = 0 POL(l) = 0 POL(pair(x_1, x_2)) = 2 + x_1 + x_2 POL(s(x_1)) = x_1 POL(t(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: g(x, x) -> h(x, x) ---------------------------------------- (8) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(x) -> U1(s(x), x) U1(t(y), x) -> pair(x, y) c -> e k -> e l -> e s(c) -> t(k) s(c) -> t(l) s(e) -> t(e) Q is empty. ---------------------------------------- (9) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(U1(x_1, x_2)) = x_1 + x_2 POL(c) = 2 POL(e) = 0 POL(f(x_1)) = 2 + 2*x_1 POL(k) = 0 POL(l) = 0 POL(pair(x_1, x_2)) = x_1 + 2*x_2 POL(s(x_1)) = x_1 POL(t(x_1)) = 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(x) -> U1(s(x), x) c -> e s(c) -> t(k) s(c) -> t(l) ---------------------------------------- (10) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: U1(t(y), x) -> pair(x, y) k -> e l -> e s(e) -> t(e) Q is empty. ---------------------------------------- (11) QTRSRRRProof (EQUIVALENT) Used ordering: Knuth-Bendix order [KBO] with precedence:s_1 > l > k > e > t_1 > U1_2 > pair_2 and weight map: k=1 e=1 l=1 t_1=1 s_1=1 U1_2=0 pair_2=1 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: U1(t(y), x) -> pair(x, y) k -> e l -> e s(e) -> t(e) ---------------------------------------- (12) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (13) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (14) YES