/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files


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WORST_CASE(?, O(1))
proof of /export/starexec/sandbox/benchmark/theBenchmark.koat
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, 1).

(0) CpxIntTrs
(1) Koat Proof [FINISHED, 10 ms]
(2) BOUNDS(1, 1)


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(0)
Obligation:
Complexity Int TRS consisting of the following rules:
eval(A) -> Com_1(eval(-(2) + 2 * B)) :|: 2 * B >= 0 && A >= 1 + 2 * B && A <= 1 + 2 * B
start(A) -> Com_1(eval(A)) :|: TRUE

The start-symbols are:[start_1]


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(1) Koat Proof (FINISHED)
YES(?, 2)



Initial complexity problem:

1:	T:

		(Comp: ?, Cost: 1)    eval(Ar_0) -> Com_1(eval(2*Fresh_0 - 2)) [ 2*Fresh_0 >= 0 /\ Ar_0 = 2*Fresh_0 + 1 ]

		(Comp: ?, Cost: 1)    start(Ar_0) -> Com_1(eval(Ar_0))

		(Comp: 1, Cost: 0)    koat_start(Ar_0) -> Com_1(start(Ar_0)) [ 0 <= 0 ]

	start location:	koat_start

	leaf cost:	0



Repeatedly propagating knowledge in problem 1 produces the following problem:

2:	T:

		(Comp: 1, Cost: 1)    eval(Ar_0) -> Com_1(eval(2*Fresh_0 - 2)) [ 2*Fresh_0 >= 0 /\ Ar_0 = 2*Fresh_0 + 1 ]

		(Comp: 1, Cost: 1)    start(Ar_0) -> Com_1(eval(Ar_0))

		(Comp: 1, Cost: 0)    koat_start(Ar_0) -> Com_1(start(Ar_0)) [ 0 <= 0 ]

	start location:	koat_start

	leaf cost:	0



Complexity upper bound 2



Time: 0.020 sec (SMT: 0.020 sec)


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(2)
BOUNDS(1, 1)