/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 139 ms] (2) BOUNDS(1, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: eval(A, B, C) -> Com_1(eval(A + 1, B + A, C)) :|: A >= B eval(A, B, C) -> Com_1(eval(A - C, B + C * C, C - 1)) :|: A >= B start(A, B, C) -> Com_1(eval(A, B, C)) :|: TRUE The start-symbols are:[start_3] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: start 0: eval -> eval : A'=1+A, B'=A+B, [ A>=B ], cost: 1 1: eval -> eval : A'=-C+A, B'=C^2+B, C'=-1+C, [ A>=B ], cost: 1 2: start -> eval : [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 2: start -> eval : [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 0. Accelerating the following rules: 0: eval -> eval : A'=1+A, B'=A+B, [ A>=B ], cost: 1 1: eval -> eval : A'=-C+A, B'=C^2+B, C'=-1+C, [ A>=B ], cost: 1 Found no metering function for rule 0. Found no metering function for rule 1 (rule is too complicated). Removing the simple loops:. Accelerated all simple loops using metering functions (where possible): Start location: start 0: eval -> eval : A'=1+A, B'=A+B, [ A>=B ], cost: 1 1: eval -> eval : A'=-C+A, B'=C^2+B, C'=-1+C, [ A>=B ], cost: 1 2: start -> eval : [], cost: 1 Chained accelerated rules (with incoming rules): Start location: start 2: start -> eval : [], cost: 1 3: start -> eval : A'=1+A, B'=A+B, [ A>=B ], cost: 2 4: start -> eval : A'=-C+A, B'=C^2+B, C'=-1+C, [ A>=B ], cost: 2 Removed unreachable locations (and leaf rules with constant cost): Start location: start ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: start Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?) ---------------------------------------- (2) BOUNDS(1, INF)