/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 217 ms] (2) BOUNDS(INF, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: f0(A, B, C) -> Com_1(f15(2, B, C)) :|: TRUE f15(A, B, C) -> Com_1(f18(A, A, C)) :|: 10 >= A f18(A, B, C) -> Com_1(f18(A, B - 1, F)) :|: D >= E + 1 f18(A, B, C) -> Com_1(f15(A + 1, B, C)) :|: TRUE f15(A, B, C) -> Com_1(f28(A, B, C)) :|: A >= 11 The start-symbols are:[f0_3] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 1: f15 -> f18 : B'=A, [ 10>=A ], cost: 1 4: f15 -> f28 : [ A>=11 ], cost: 1 2: f18 -> f18 : B'=-1+B, C'=free, [ free_1>=1+free_2 ], cost: 1 3: f18 -> f15 : A'=1+A, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 0: f0 -> f15 : A'=2, [], cost: 1 Removed unreachable and leaf rules: Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 1: f15 -> f18 : B'=A, [ 10>=A ], cost: 1 2: f18 -> f18 : B'=-1+B, C'=free, [ free_1>=1+free_2 ], cost: 1 3: f18 -> f15 : A'=1+A, [], cost: 1 Simplified all rules, resulting in: Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 1: f15 -> f18 : B'=A, [ 10>=A ], cost: 1 2: f18 -> f18 : B'=-1+B, C'=free, [], cost: 1 3: f18 -> f15 : A'=1+A, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 2. Accelerating the following rules: 2: f18 -> f18 : B'=-1+B, C'=free, [], cost: 1 Accelerated rule 2 with NONTERM, yielding the new rule 5. Removing the simple loops: 2. Accelerated all simple loops using metering functions (where possible): Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 1: f15 -> f18 : B'=A, [ 10>=A ], cost: 1 3: f18 -> f15 : A'=1+A, [], cost: 1 5: f18 -> [4] : [], cost: NONTERM Chained accelerated rules (with incoming rules): Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 1: f15 -> f18 : B'=A, [ 10>=A ], cost: 1 6: f15 -> [4] : B'=A, [ 10>=A ], cost: NONTERM 3: f18 -> f15 : A'=1+A, [], cost: 1 Eliminated locations (on linear paths): Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 6: f15 -> [4] : B'=A, [ 10>=A ], cost: NONTERM 7: f15 -> f15 : A'=1+A, B'=A, [ 10>=A ], cost: 2 Accelerating simple loops of location 1. Accelerating the following rules: 7: f15 -> f15 : A'=1+A, B'=A, [ 10>=A ], cost: 2 Accelerated rule 7 with metering function 11-A, yielding the new rule 8. Removing the simple loops: 7. Accelerated all simple loops using metering functions (where possible): Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 6: f15 -> [4] : B'=A, [ 10>=A ], cost: NONTERM 8: f15 -> f15 : A'=11, B'=10, [ 10>=A ], cost: 22-2*A Chained accelerated rules (with incoming rules): Start location: f0 0: f0 -> f15 : A'=2, [], cost: 1 9: f0 -> f15 : A'=11, B'=10, [], cost: 19 6: f15 -> [4] : B'=A, [ 10>=A ], cost: NONTERM Eliminated locations (on tree-shaped paths): Start location: f0 10: f0 -> [4] : A'=2, B'=2, [], cost: NONTERM ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: f0 10: f0 -> [4] : A'=2, B'=2, [], cost: NONTERM Computing asymptotic complexity for rule 10 Guard is satisfiable, yielding nontermination Resulting cost NONTERM has complexity: Nonterm Found new complexity Nonterm. Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Nonterm Cpx degree: Nonterm Solved cost: NONTERM Rule cost: NONTERM Rule guard: [] NO ---------------------------------------- (2) BOUNDS(INF, INF)