/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x:S y:S) (RULES bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ) Problem 1: Innermost Equivalent Processor: -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: BITITER(x:S,y:S) -> IF(zero(x:S),x:S,inc(y:S)) BITITER(x:S,y:S) -> INC(y:S) BITITER(x:S,y:S) -> ZERO(x:S) BITS(x:S) -> BITITER(x:S,0) HALF(s(s(x:S))) -> HALF(x:S) IF(ffalse,x:S,y:S) -> BITITER(half(x:S),y:S) IF(ffalse,x:S,y:S) -> HALF(x:S) IF(ttrue,x:S,y:S) -> P(y:S) INC(s(x:S)) -> INC(x:S) -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse Problem 1: SCC Processor: -> Pairs: BITITER(x:S,y:S) -> IF(zero(x:S),x:S,inc(y:S)) BITITER(x:S,y:S) -> INC(y:S) BITITER(x:S,y:S) -> ZERO(x:S) BITS(x:S) -> BITITER(x:S,0) HALF(s(s(x:S))) -> HALF(x:S) IF(ffalse,x:S,y:S) -> BITITER(half(x:S),y:S) IF(ffalse,x:S,y:S) -> HALF(x:S) IF(ttrue,x:S,y:S) -> P(y:S) INC(s(x:S)) -> INC(x:S) -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: INC(s(x:S)) -> INC(x:S) ->->-> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->->Cycle: ->->-> Pairs: HALF(s(s(x:S))) -> HALF(x:S) ->->-> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->->Cycle: ->->-> Pairs: BITITER(x:S,y:S) -> IF(zero(x:S),x:S,inc(y:S)) IF(ffalse,x:S,y:S) -> BITITER(half(x:S),y:S) ->->-> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse The problem is decomposed in 3 subproblems. Problem 1.1: Subterm Processor: -> Pairs: INC(s(x:S)) -> INC(x:S) -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Projection: pi(INC) = 1 Problem 1.1: SCC Processor: -> Pairs: Empty -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: Subterm Processor: -> Pairs: HALF(s(s(x:S))) -> HALF(x:S) -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Projection: pi(HALF) = 1 Problem 1.2: SCC Processor: -> Pairs: Empty -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.3: Reduction Pairs Processor: -> Pairs: BITITER(x:S,y:S) -> IF(zero(x:S),x:S,inc(y:S)) IF(ffalse,x:S,y:S) -> BITITER(half(x:S),y:S) -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse -> Usable rules: half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Interpretation type: Linear ->Coefficients: All rationals ->Dimension: 1 ->Bound: 2 ->Interpretation: [bitIter](X1,X2) = 0 [bits](X) = 0 [half](X) = 1/2.X [if](X1,X2,X3) = 0 [inc](X) = 2.X + 1 [p](X) = 0 [zero](X) = X + 1 [0] = 0 [fSNonEmpty] = 0 [false] = 2 [s](X) = 2.X + 2 [true] = 1 [BITITER](X1,X2) = 2.X1 + 2 [BITS](X) = 0 [HALF](X) = 0 [IF](X1,X2,X3) = X1 + X2 + 1/2 [INC](X) = 0 [P](X) = 0 [ZERO](X) = 0 Problem 1.3: SCC Processor: -> Pairs: IF(ffalse,x:S,y:S) -> BITITER(half(x:S),y:S) -> Rules: bitIter(x:S,y:S) -> if(zero(x:S),x:S,inc(y:S)) bits(x:S) -> bitIter(x:S,0) half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> bitIter(half(x:S),y:S) if(ttrue,x:S,y:S) -> p(y:S) inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) p(0) -> 0 p(s(x:S)) -> x:S zero(0) -> ttrue zero(s(x:S)) -> ffalse ->Strongly Connected Components: There is no strongly connected component The problem is finite.