/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 124 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 26 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 12 ms] (6) QTRS (7) QTRSRRRProof [EQUIVALENT, 25 ms] (8) QTRS (9) QTRSRRRProof [EQUIVALENT, 0 ms] (10) QTRS (11) RisEmptyProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(2nd(cons(X, cons(Y, Z)))) -> mark(Y) active(from(X)) -> mark(cons(X, from(s(X)))) active(2nd(X)) -> 2nd(active(X)) active(cons(X1, X2)) -> cons(active(X1), X2) active(from(X)) -> from(active(X)) active(s(X)) -> s(active(X)) 2nd(mark(X)) -> mark(2nd(X)) cons(mark(X1), X2) -> mark(cons(X1, X2)) from(mark(X)) -> mark(from(X)) s(mark(X)) -> mark(s(X)) proper(2nd(X)) -> 2nd(proper(X)) proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) proper(from(X)) -> from(proper(X)) proper(s(X)) -> s(proper(X)) 2nd(ok(X)) -> ok(2nd(X)) cons(ok(X1), ok(X2)) -> ok(cons(X1, X2)) from(ok(X)) -> ok(from(X)) s(ok(X)) -> ok(s(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(2nd(x_1)) = 2*x_1 POL(active(x_1)) = 2*x_1 POL(cons(x_1, x_2)) = x_1 + x_2 POL(from(x_1)) = x_1 POL(mark(x_1)) = x_1 POL(ok(x_1)) = 1 + 2*x_1 POL(proper(x_1)) = x_1 POL(s(x_1)) = x_1 POL(top(x_1)) = 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 2nd(ok(X)) -> ok(2nd(X)) cons(ok(X1), ok(X2)) -> ok(cons(X1, X2)) top(ok(X)) -> top(active(X)) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(2nd(cons(X, cons(Y, Z)))) -> mark(Y) active(from(X)) -> mark(cons(X, from(s(X)))) active(2nd(X)) -> 2nd(active(X)) active(cons(X1, X2)) -> cons(active(X1), X2) active(from(X)) -> from(active(X)) active(s(X)) -> s(active(X)) 2nd(mark(X)) -> mark(2nd(X)) cons(mark(X1), X2) -> mark(cons(X1, X2)) from(mark(X)) -> mark(from(X)) s(mark(X)) -> mark(s(X)) proper(2nd(X)) -> 2nd(proper(X)) proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) proper(from(X)) -> from(proper(X)) proper(s(X)) -> s(proper(X)) from(ok(X)) -> ok(from(X)) s(ok(X)) -> ok(s(X)) top(mark(X)) -> top(proper(X)) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(2nd(x_1)) = 1 + 2*x_1 POL(active(x_1)) = 2*x_1 POL(cons(x_1, x_2)) = 2*x_1 + x_2 POL(from(x_1)) = 2*x_1 POL(mark(x_1)) = x_1 POL(ok(x_1)) = 2*x_1 POL(proper(x_1)) = x_1 POL(s(x_1)) = x_1 POL(top(x_1)) = 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: active(2nd(cons(X, cons(Y, Z)))) -> mark(Y) active(2nd(X)) -> 2nd(active(X)) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(from(X)) -> mark(cons(X, from(s(X)))) active(cons(X1, X2)) -> cons(active(X1), X2) active(from(X)) -> from(active(X)) active(s(X)) -> s(active(X)) 2nd(mark(X)) -> mark(2nd(X)) cons(mark(X1), X2) -> mark(cons(X1, X2)) from(mark(X)) -> mark(from(X)) s(mark(X)) -> mark(s(X)) proper(2nd(X)) -> 2nd(proper(X)) proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) proper(from(X)) -> from(proper(X)) proper(s(X)) -> s(proper(X)) from(ok(X)) -> ok(from(X)) s(ok(X)) -> ok(s(X)) top(mark(X)) -> top(proper(X)) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(2nd(x_1)) = x_1 POL(active(x_1)) = 2*x_1 POL(cons(x_1, x_2)) = x_1 + x_2 POL(from(x_1)) = 2*x_1 POL(mark(x_1)) = x_1 POL(ok(x_1)) = 2 + 2*x_1 POL(proper(x_1)) = x_1 POL(s(x_1)) = x_1 POL(top(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: from(ok(X)) -> ok(from(X)) ---------------------------------------- (6) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(from(X)) -> mark(cons(X, from(s(X)))) active(cons(X1, X2)) -> cons(active(X1), X2) active(from(X)) -> from(active(X)) active(s(X)) -> s(active(X)) 2nd(mark(X)) -> mark(2nd(X)) cons(mark(X1), X2) -> mark(cons(X1, X2)) from(mark(X)) -> mark(from(X)) s(mark(X)) -> mark(s(X)) proper(2nd(X)) -> 2nd(proper(X)) proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) proper(from(X)) -> from(proper(X)) proper(s(X)) -> s(proper(X)) s(ok(X)) -> ok(s(X)) top(mark(X)) -> top(proper(X)) Q is empty. ---------------------------------------- (7) QTRSRRRProof (EQUIVALENT) Used ordering: active/1(YES) from/1(YES) mark/1)YES( cons/2(YES,YES) s/1(YES) 2nd/1(YES) proper/1)YES( ok/1(YES) top/1)YES( Quasi precedence: active_1 > cons_2 > from_1 active_1 > s_1 > ok_1 > from_1 2nd_1 > from_1 Status: active_1: multiset status from_1: multiset status cons_2: multiset status s_1: multiset status 2nd_1: multiset status ok_1: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: active(from(X)) -> mark(cons(X, from(s(X)))) active(cons(X1, X2)) -> cons(active(X1), X2) active(from(X)) -> from(active(X)) active(s(X)) -> s(active(X)) s(ok(X)) -> ok(s(X)) ---------------------------------------- (8) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 2nd(mark(X)) -> mark(2nd(X)) cons(mark(X1), X2) -> mark(cons(X1, X2)) from(mark(X)) -> mark(from(X)) s(mark(X)) -> mark(s(X)) proper(2nd(X)) -> 2nd(proper(X)) proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) proper(from(X)) -> from(proper(X)) proper(s(X)) -> s(proper(X)) top(mark(X)) -> top(proper(X)) Q is empty. ---------------------------------------- (9) QTRSRRRProof (EQUIVALENT) Used ordering: Knuth-Bendix order [KBO] with precedence:proper_1 > top_1 > s_1 > 2nd_1 > from_1 > cons_2 > mark_1 and weight map: 2nd_1=2 mark_1=1 from_1=2 s_1=2 proper_1=0 top_1=1 cons_2=0 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 2nd(mark(X)) -> mark(2nd(X)) cons(mark(X1), X2) -> mark(cons(X1, X2)) from(mark(X)) -> mark(from(X)) s(mark(X)) -> mark(s(X)) proper(2nd(X)) -> 2nd(proper(X)) proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) proper(from(X)) -> from(proper(X)) proper(s(X)) -> s(proper(X)) top(mark(X)) -> top(proper(X)) ---------------------------------------- (10) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (11) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (12) YES