/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x:S y:S z:S) (RULES div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) ) Problem 1: Dependency Pairs Processor: -> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(s(x:S),s(y:S),z:S) -> QUOT(x:S,y:S,z:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) -> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) Problem 1: SCC Processor: -> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(s(x:S),s(y:S),z:S) -> QUOT(x:S,y:S,z:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) -> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(s(x:S),s(y:S),z:S) -> QUOT(x:S,y:S,z:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) ->->-> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) Problem 1: Subterm Processor: -> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(s(x:S),s(y:S),z:S) -> QUOT(x:S,y:S,z:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) -> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) ->Projection: pi(DIV) = 1 pi(QUOT) = 1 Problem 1: SCC Processor: -> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) -> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) ->->-> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) Problem 1: Reduction Pair Processor: -> Pairs: DIV(x:S,y:S) -> QUOT(x:S,y:S,y:S) QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) -> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [0] = 2 [s](X) = 0 [DIV](X1,X2) = 2.X1 + 2.X2 + 2 [QUOT](X1,X2,X3) = 2.X1 + X2 + X3 Problem 1: SCC Processor: -> Pairs: QUOT(x:S,0,s(z:S)) -> DIV(x:S,s(z:S)) -> Rules: div(0,y:S) -> 0 div(x:S,y:S) -> quot(x:S,y:S,y:S) quot(0,s(y:S),z:S) -> 0 quot(s(x:S),s(y:S),z:S) -> quot(x:S,y:S,z:S) quot(x:S,0,s(z:S)) -> s(div(x:S,s(z:S))) ->Strongly Connected Components: There is no strongly connected component The problem is finite.