/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 f(x,empty()) -> x
 f(empty(),cons(a,k)) -> f(cons(a,k),k)
 f(cons(a,k),y) -> f(y,k)

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [f](x0, x1) = x0 + 5x1 + 2,
   
   [empty] = 3,
   
   [cons](x0, x1) = x0 + 6x1 + 4
  orientation:
   f(x,empty()) = x + 17 >= x = x
   
   f(empty(),cons(a,k)) = 5a + 30k + 25 >= a + 11k + 6 = f(cons(a,k),k)
   
   f(cons(a,k),y) = a + 6k + 5y + 6 >= 5k + y + 2 = f(y,k)
  problem:
   
  Qed