/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S X:S Y:S) (RULES div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ) Problem 1: Innermost Equivalent Processor: -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: DIV(s(X:S),s(Y:S)) -> DIV(minus(X:S,Y:S),s(Y:S)) DIV(s(X:S),s(Y:S)) -> MINUS(X:S,Y:S) MINUS(s(X:S),s(Y:S)) -> MINUS(X:S,Y:S) MINUS(s(X:S),s(Y:S)) -> P(minus(X:S,Y:S)) -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S Problem 1: SCC Processor: -> Pairs: DIV(s(X:S),s(Y:S)) -> DIV(minus(X:S,Y:S),s(Y:S)) DIV(s(X:S),s(Y:S)) -> MINUS(X:S,Y:S) MINUS(s(X:S),s(Y:S)) -> MINUS(X:S,Y:S) MINUS(s(X:S),s(Y:S)) -> P(minus(X:S,Y:S)) -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: MINUS(s(X:S),s(Y:S)) -> MINUS(X:S,Y:S) ->->-> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ->->Cycle: ->->-> Pairs: DIV(s(X:S),s(Y:S)) -> DIV(minus(X:S,Y:S),s(Y:S)) ->->-> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S The problem is decomposed in 2 subproblems. Problem 1.1: Subterm Processor: -> Pairs: MINUS(s(X:S),s(Y:S)) -> MINUS(X:S,Y:S) -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ->Projection: pi(MINUS) = 1 Problem 1.1: SCC Processor: -> Pairs: Empty -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: Reduction Pairs Processor: -> Pairs: DIV(s(X:S),s(Y:S)) -> DIV(minus(X:S,Y:S),s(Y:S)) -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S -> Usable rules: minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [div](X1,X2) = 0 [minus](X1,X2) = X1 + 1 [p](X) = 2.X + 1 [0] = 0 [fSNonEmpty] = 0 [s](X) = 2.X + 2 [DIV](X1,X2) = 2.X1 [MINUS](X1,X2) = 0 [P](X) = 0 Problem 1.2: SCC Processor: -> Pairs: Empty -> Rules: div(0,s(Y:S)) -> 0 div(s(X:S),s(Y:S)) -> s(div(minus(X:S,Y:S),s(Y:S))) minus(s(X:S),s(Y:S)) -> p(minus(X:S,Y:S)) minus(X:S,0) -> X:S p(s(X:S)) -> X:S ->Strongly Connected Components: There is no strongly connected component The problem is finite.