/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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NO

** BEGIN proof argument **
The following pattern rule was generated by the strategy
presented in Sect. 3 of [Emmes, Enger, Giesl, IJCAR'12]:
[iteration = 4] f(tt,s(s(_0))){_0->s(_0)}^n{_0->0} -> f(tt,s(s(s(_0)))){_0->s(_0)}^n{_0->0}
We apply Theorem 8 of [Emmes, Enger, Giesl, IJCAR'12]
on this rule with m = 1, b = 1, pi = epsilon,
sigma' = {} and mu' = {}.
Hence the term f(tt,s(s(0))), obtained from
instantiating n with 0 in the left-hand side of
the rule, starts an infinite derivation w.r.t.
the analyzed TRS.
** END proof argument **

** BEGIN proof description **
## Searching for a generalized rewrite rule
(a rule whose right-hand side contains a variable
that does not occur in the left-hand side)...
No generalized rewrite rule found!

## Applying the DP framework...
## 3 initial DP problems to solve.
## First, we try to decompose these problems into smaller problems.
## Round 1 [3 DP problems]:
  ## DP problem:
  Dependency pairs = [f^#(tt,_0) -> f^#(eq(toOne(_0),s(0)),s(_0))]
  TRS = {f(tt,_0) -> f(eq(toOne(_0),s(0)),s(_0)), eq(s(_0),s(_1)) -> eq(_0,_1), eq(0,0) -> tt, toOne(s(s(_0))) -> toOne(s(_0)), toOne(s(0)) -> s(0)}
    ## Trying with homeomorphic embeddings... Failed!
    ## Trying with polynomial interpretations... Failed!
    ## Trying with lexicographic path orders... Failed!
    ## Trying with Knuth-Bendix orders... Failed!
  Don't know whether this DP problem is finite.
  ## DP problem:
  Dependency pairs = [toOne^#(s(s(_0))) -> toOne^#(s(_0))]
  TRS = {f(tt,_0) -> f(eq(toOne(_0),s(0)),s(_0)), eq(s(_0),s(_1)) -> eq(_0,_1), eq(0,0) -> tt, toOne(s(s(_0))) -> toOne(s(_0)), toOne(s(0)) -> s(0)}
    ## Trying with homeomorphic embeddings... Success!
  This DP problem is finite.
  ## DP problem:
  Dependency pairs = [eq^#(s(_0),s(_1)) -> eq^#(_0,_1)]
  TRS = {f(tt,_0) -> f(eq(toOne(_0),s(0)),s(_0)), eq(s(_0),s(_1)) -> eq(_0,_1), eq(0,0) -> tt, toOne(s(s(_0))) -> toOne(s(_0)), toOne(s(0)) -> s(0)}
    ## Trying with homeomorphic embeddings... Success!
  This DP problem is finite.
## A DP problem could not be proved finite.
## Now, we try to prove that this problem is infinite.
    ## Trying to prove non-looping nontermination
      # Iteration 0: non-looping nontermination not proved, 1 unfolded rule generated.
      # Iteration 1: non-looping nontermination not proved, 5 unfolded rules generated.
      # Iteration 2: non-looping nontermination not proved, 16 unfolded rules generated.
      # Iteration 3: non-looping nontermination not proved, 43 unfolded rules generated.
      # Iteration 4: success, non-looping nontermination proved, 98 unfolded rules generated.
      Here is the successful unfolding. Let IR be the TRS under analysis.
      IR contains the dependency pair f^#(tt,_0) -> f^#(eq(toOne(_0),s(0)),s(_0)).
      We apply (I) of [Emmes, Enger, Giesl, IJCAR'12] to this dependency pair.
      ==> P0 = f^#(tt,_0){}^n{} -> f^#(eq(toOne(_0),s(0)),s(_0)){}^n{} is in U_IR^0.
      We apply (VI) of [Emmes, Enger, Giesl, IJCAR'12] to this pattern rule
      at position [0, 0] using the pattern rule
      toOne(s(s(_0))){_0->s(_0)}^n{_0->_1} -> toOne(s(_1)){_0->s(_0)}^n{_0->_1}
      obtained from IR.
      ==> P1 = f^#(tt,s(s(_0))){_0->s(_0)}^n{_0->_1} -> f^#(eq(toOne(s(_1)),s(0)),s(s(s(_0)))){_0->s(_0)}^n{_0->_1} is in U_IR^1.
      We apply (V) + (IX) of [Emmes, Enger, Giesl, IJCAR'12] to this pattern rule
      at position [0, 0] using the rule
      toOne(s(0)) -> s(0)
      of IR.
      ==> P2 = f^#(tt,s(s(_0))){_0->s(_0)}^n{_0->0} -> f^#(eq(s(0),s(0)),s(s(s(_0)))){_0->s(_0)}^n{_0->0} is in U_IR^2.
      We apply (IX) of [Emmes, Enger, Giesl, IJCAR'12] to this pattern rule
      at position [0] using the rule
      eq(s(_0),s(_1)) -> eq(_0,_1)
      of IR.
      ==> P3 = f^#(tt,s(s(_0))){_0->s(_0)}^n{_0->0} -> f^#(eq(0,0),s(s(s(_0)))){_0->s(_0)}^n{_0->0} is in U_IR^3.
      We apply (IX) of [Emmes, Enger, Giesl, IJCAR'12] to this pattern rule
      at position [0] using the rule
      eq(0,0) -> tt
      of IR.
      ==> P4 = f^#(tt,s(s(_0))){_0->s(_0)}^n{_0->0} -> f^#(tt,s(s(s(_0)))){_0->s(_0)}^n{_0->0} is in U_IR^4.
  This DP problem is infinite.
Proof run on Linux version 3.10.0-1160.25.1.el7.x86_64 for amd64
using Java version 1.8.0_292
** END proof description **
Total number of generated unfolded rules = 482