/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(f(),a(f(),x)) -> a(x,x) a(h(),x) -> a(f(),a(g(),a(f(),x))) Proof: Extended Uncurrying Processor: application symbol: a symbol table: g ==> g0/0 g1/1 h ==> h0/0 h1/1 f ==> f0/0 f1/1 uncurry-rules: a(f0(),x1) -> f1(x1) a(h0(),x3) -> h1(x3) a(g0(),x5) -> g1(x5) eta-rules: problem: f1(f1(x)) -> a(x,x) h1(x) -> f1(g1(f1(x))) a(f0(),x1) -> f1(x1) a(h0(),x3) -> h1(x3) a(g0(),x5) -> g1(x5) Matrix Interpretation Processor: dim=3 interpretation: [1] [f0] = [0] [1], [1] [g0] = [0] [1], [1 0 1] [1 1 1] [a](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [1 0 0] [1 1 1] , [1 0 1] [f1](x0) = [0 0 0]x0 [1 1 1] , [1 0 1] [h1](x0) = [0 0 0]x0 [1 1 1] , [1 1 0] [g1](x0) = [0 0 0]x0 [0 1 0] , [0] [h0] = [0] [1] orientation: [2 1 2] [2 1 2] f1(f1(x)) = [0 0 0]x >= [0 0 0]x = a(x,x) [2 1 2] [2 1 1] [1 0 1] [1 0 1] h1(x) = [0 0 0]x >= [0 0 0]x = f1(g1(f1(x))) [1 1 1] [1 0 1] [1 1 1] [2] [1 0 1] a(f0(),x1) = [0 0 0]x1 + [0] >= [0 0 0]x1 = f1(x1) [1 1 1] [1] [1 1 1] [1 1 1] [1] [1 0 1] a(h0(),x3) = [0 0 0]x3 + [0] >= [0 0 0]x3 = h1(x3) [1 1 1] [0] [1 1 1] [1 1 1] [2] [1 1 0] a(g0(),x5) = [0 0 0]x5 + [0] >= [0 0 0]x5 = g1(x5) [1 1 1] [1] [0 1 0] problem: f1(f1(x)) -> a(x,x) h1(x) -> f1(g1(f1(x))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 1 0] [a](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [1 1 1] [1 1 1] , [1 0 1] [f1](x0) = [0 1 0]x0 [1 1 1] , [1 1 1] [1] [h1](x0) = [1 1 0]x0 + [1] [1 0 1] [1], [1 0 0] [0] [g1](x0) = [0 0 0]x0 + [1] [0 0 0] [0] orientation: [2 1 2] [2 1 0] f1(f1(x)) = [0 1 0]x >= [0 0 0]x = a(x,x) [2 2 2] [2 2 2] [1 1 1] [1] [1 0 1] [0] h1(x) = [1 1 0]x + [1] >= [0 0 0]x + [1] = f1(g1(f1(x))) [1 0 1] [1] [1 0 1] [1] problem: f1(f1(x)) -> a(x,x) Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [1 0 0] [0] [a](x0, x1) = [0 0 0]x0 + [0 1 0]x1 + [1] [0 0 0] [0 0 0] [0], [1 1 1] [0] [f1](x0) = [1 0 0]x0 + [1] [0 0 0] [1] orientation: [2 1 1] [2] [2 1 0] [0] f1(f1(x)) = [1 1 1]x + [1] >= [0 1 0]x + [1] = a(x,x) [0 0 0] [1] [0 0 0] [0] problem: Qed