/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 72 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 0 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 12 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: double(0) -> 0 double(s(x)) -> s(s(double(x))) +(x, 0) -> x +(x, s(y)) -> s(+(x, y)) +(s(x), y) -> s(+(x, y)) double(x) -> +(x, x) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(+(x_1, x_2)) = x_1 + x_2 POL(0) = 1 POL(double(x_1)) = 2*x_1 POL(s(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: double(0) -> 0 +(x, 0) -> x ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: double(s(x)) -> s(s(double(x))) +(x, s(y)) -> s(+(x, y)) +(s(x), y) -> s(+(x, y)) double(x) -> +(x, x) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: double/1(YES) s/1)YES( +/2(YES,YES) Quasi precedence: double_1 > +_2 Status: double_1: [1] +_2: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: double(x) -> +(x, x) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: double(s(x)) -> s(s(double(x))) +(x, s(y)) -> s(+(x, y)) +(s(x), y) -> s(+(x, y)) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: double_1 > s_1 +_2 > s_1 Status: double_1: multiset status s_1: multiset status +_2: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: double(s(x)) -> s(s(double(x))) +(x, s(y)) -> s(+(x, y)) +(s(x), y) -> s(+(x, y)) ---------------------------------------- (6) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (7) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (8) YES