/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(b(x)) -> b(a(x))
 a(c(x)) -> x

Proof:
 KBO Processor:
  weight function:
   w0 = 1
   w(c) = w(b) = 1
   w(a) = 0
  precedence:
   a > b > c
  problem:
   
  Qed