/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES

Problem:
 *(i(x),x) -> 1()
 *(1(),y) -> y
 *(x,0()) -> 0()
 *(*(x,y),z) -> *(x,*(y,z))

Proof:
 Matrix Interpretation Processor: dim=3
  
  interpretation:
                 [1 0 0]          [1]
   [*](x0, x1) = [0 1 0]x0 + x1 + [0]
                 [0 1 0]          [0],
   
         [0]
   [0] = [1]
         [0],
   
             [1 0 0]     [1]
   [i](x0) = [1 0 1]x0 + [0]
             [0 0 0]     [0],
   
         [1]
   [1] = [0]
         [0]
  orientation:
               [2 0 0]    [2]    [1]      
   *(i(x),x) = [1 1 1]x + [0] >= [0] = 1()
               [1 0 2]    [0]    [0]      
   
                  [2]         
   *(1(),y) = y + [0] >= y = y
                  [0]         
   
              [1 0 0]    [1]    [0]      
   *(x,0()) = [0 1 0]x + [1] >= [1] = 0()
              [0 1 0]    [0]    [0]      
   
                 [1 0 0]    [1 0 0]        [2]    [1 0 0]    [1 0 0]        [2]              
   *(*(x,y),z) = [0 1 0]x + [0 1 0]y + z + [0] >= [0 1 0]x + [0 1 0]y + z + [0] = *(x,*(y,z))
                 [0 1 0]    [0 1 0]        [0]    [0 1 0]    [0 1 0]        [0]              
  problem:
   *(*(x,y),z) -> *(x,*(y,z))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [*](x0, x1) = 2x0 + x1 + 2
   orientation:
    *(*(x,y),z) = 4x + 2y + z + 6 >= 2x + 2y + z + 4 = *(x,*(y,z))
   problem:
    
   Qed