/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES

Problem 1: 

(VAR v_NonEmpty:S x:S y:S)
(RULES
if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
if_minus(ttrue,s(x:S),y:S) -> 0
if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
le(0,y:S) -> ttrue
le(s(x:S),0) -> ffalse
le(s(x:S),s(y:S)) -> le(x:S,y:S)
minus(0,y:S) -> 0
minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
mod(0,y:S) -> 0
mod(s(x:S),0) -> 0
mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
)

Problem 1: 

Innermost Equivalent Processor:
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
-> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination.
 

Problem 1: 

Dependency Pairs Processor:
-> Pairs:
 IF_MINUS(ffalse,s(x:S),y:S) -> MINUS(x:S,y:S)
 IF_MOD(ttrue,s(x:S),s(y:S)) -> MINUS(x:S,y:S)
 IF_MOD(ttrue,s(x:S),s(y:S)) -> MOD(minus(x:S,y:S),s(y:S))
 LE(s(x:S),s(y:S)) -> LE(x:S,y:S)
 MINUS(s(x:S),y:S) -> IF_MINUS(le(s(x:S),y:S),s(x:S),y:S)
 MINUS(s(x:S),y:S) -> LE(s(x:S),y:S)
 MOD(s(x:S),s(y:S)) -> IF_MOD(le(y:S,x:S),s(x:S),s(y:S))
 MOD(s(x:S),s(y:S)) -> LE(y:S,x:S)
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))

Problem 1: 

SCC Processor:
-> Pairs:
 IF_MINUS(ffalse,s(x:S),y:S) -> MINUS(x:S,y:S)
 IF_MOD(ttrue,s(x:S),s(y:S)) -> MINUS(x:S,y:S)
 IF_MOD(ttrue,s(x:S),s(y:S)) -> MOD(minus(x:S,y:S),s(y:S))
 LE(s(x:S),s(y:S)) -> LE(x:S,y:S)
 MINUS(s(x:S),y:S) -> IF_MINUS(le(s(x:S),y:S),s(x:S),y:S)
 MINUS(s(x:S),y:S) -> LE(s(x:S),y:S)
 MOD(s(x:S),s(y:S)) -> IF_MOD(le(y:S,x:S),s(x:S),s(y:S))
 MOD(s(x:S),s(y:S)) -> LE(y:S,x:S)
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->Strongly Connected Components:
->->Cycle:
->->-> Pairs:
 LE(s(x:S),s(y:S)) -> LE(x:S,y:S)
->->-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->->Cycle:
->->-> Pairs:
 IF_MINUS(ffalse,s(x:S),y:S) -> MINUS(x:S,y:S)
 MINUS(s(x:S),y:S) -> IF_MINUS(le(s(x:S),y:S),s(x:S),y:S)
->->-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->->Cycle:
->->-> Pairs:
 IF_MOD(ttrue,s(x:S),s(y:S)) -> MOD(minus(x:S,y:S),s(y:S))
 MOD(s(x:S),s(y:S)) -> IF_MOD(le(y:S,x:S),s(x:S),s(y:S))
->->-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))


The problem is decomposed in 3 subproblems.

Problem 1.1: 

Subterm Processor:
-> Pairs:
 LE(s(x:S),s(y:S)) -> LE(x:S,y:S)
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->Projection:
 pi(LE) = 1

Problem 1.1: 

SCC Processor:
-> Pairs:
 Empty
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.

Problem 1.2: 

Subterm Processor:
-> Pairs:
 IF_MINUS(ffalse,s(x:S),y:S) -> MINUS(x:S,y:S)
 MINUS(s(x:S),y:S) -> IF_MINUS(le(s(x:S),y:S),s(x:S),y:S)
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->Projection:
 pi(IF_MINUS) = 2
 pi(MINUS) = 1

Problem 1.2: 

SCC Processor:
-> Pairs:
 MINUS(s(x:S),y:S) -> IF_MINUS(le(s(x:S),y:S),s(x:S),y:S)
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.

Problem 1.3: 

Reduction Pairs Processor:
-> Pairs:
 IF_MOD(ttrue,s(x:S),s(y:S)) -> MOD(minus(x:S,y:S),s(y:S))
 MOD(s(x:S),s(y:S)) -> IF_MOD(le(y:S,x:S),s(x:S),s(y:S))
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
-> Usable rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
->Interpretation type:
 Linear
->Coefficients:
 Natural Numbers
->Dimension:
 1
->Bound:
 2
->Interpretation:
 
[if_minus](X1,X2,X3) = X2
[if_mod](X1,X2,X3) = 0
[le](X1,X2) = 2.X1 + 2.X2
[minus](X1,X2) = X1
[mod](X1,X2) = 0
[0] = 2
[fSNonEmpty] = 0
[false] = 0
[s](X) = 2.X + 2
[true] = 0
[IF_MINUS](X1,X2,X3) = 0
[IF_MOD](X1,X2,X3) = 2.X2 + 2.X3 + 2
[LE](X1,X2) = 0
[MINUS](X1,X2) = 0
[MOD](X1,X2) = 2.X1 + 2.X2 + 2

Problem 1.3: 

SCC Processor:
-> Pairs:
 MOD(s(x:S),s(y:S)) -> IF_MOD(le(y:S,x:S),s(x:S),s(y:S))
-> Rules:
 if_minus(ffalse,s(x:S),y:S) -> s(minus(x:S,y:S))
 if_minus(ttrue,s(x:S),y:S) -> 0
 if_mod(ffalse,s(x:S),s(y:S)) -> s(x:S)
 if_mod(ttrue,s(x:S),s(y:S)) -> mod(minus(x:S,y:S),s(y:S))
 le(0,y:S) -> ttrue
 le(s(x:S),0) -> ffalse
 le(s(x:S),s(y:S)) -> le(x:S,y:S)
 minus(0,y:S) -> 0
 minus(s(x:S),y:S) -> if_minus(le(s(x:S),y:S),s(x:S),y:S)
 mod(0,y:S) -> 0
 mod(s(x:S),0) -> 0
 mod(s(x:S),s(y:S)) -> if_mod(le(y:S,x:S),s(x:S),s(y:S))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.