/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Applying the DP framework... ## 3 initial DP problems to solve. ## First, we try to decompose these problems into smaller problems. ## Round 1 [3 DP problems]: ## DP problem: Dependency pairs = [conv^#(s(_0)) -> conv^#(half(s(_0)))] TRS = {half(0) -> 0, half(s(0)) -> 0, half(s(s(_0))) -> s(half(_0)), lastbit(0) -> 0, lastbit(s(0)) -> s(0), lastbit(s(s(_0))) -> lastbit(_0), conv(0) -> cons(nil,0), conv(s(_0)) -> cons(conv(half(s(_0))),lastbit(s(_0)))} ## Trying with homeomorphic embeddings... Failed! ## Trying with polynomial interpretations... Failed! ## Trying with lexicographic path orders... Failed! ## Trying with Knuth-Bendix orders... Failed! Don't know whether this DP problem is finite. ## DP problem: Dependency pairs = [lastbit^#(s(s(_0))) -> lastbit^#(_0)] TRS = {half(0) -> 0, half(s(0)) -> 0, half(s(s(_0))) -> s(half(_0)), lastbit(0) -> 0, lastbit(s(0)) -> s(0), lastbit(s(s(_0))) -> lastbit(_0), conv(0) -> cons(nil,0), conv(s(_0)) -> cons(conv(half(s(_0))),lastbit(s(_0)))} ## Trying with homeomorphic embeddings... Success! This DP problem is finite. ## DP problem: Dependency pairs = [half^#(s(s(_0))) -> half^#(_0)] TRS = {half(0) -> 0, half(s(0)) -> 0, half(s(s(_0))) -> s(half(_0)), lastbit(0) -> 0, lastbit(s(0)) -> s(0), lastbit(s(s(_0))) -> lastbit(_0), conv(0) -> cons(nil,0), conv(s(_0)) -> cons(conv(half(s(_0))),lastbit(s(_0)))} ## Trying with homeomorphic embeddings... Success! This DP problem is finite. ## A DP problem could not be proved finite. ## Now, we try to prove that this problem is infinite. ## Could not solve the following DP problems: 1: Dependency pairs = [conv^#(s(_0)) -> conv^#(half(s(_0)))] TRS = {half(0) -> 0, half(s(0)) -> 0, half(s(s(_0))) -> s(half(_0)), lastbit(0) -> 0, lastbit(s(0)) -> s(0), lastbit(s(s(_0))) -> lastbit(_0), conv(0) -> cons(nil,0), conv(s(_0)) -> cons(conv(half(s(_0))),lastbit(s(_0)))} Hence, could not prove (non)termination of the TRS under analysis. Proof run on Linux version 3.10.0-1160.25.1.el7.x86_64 for amd64 using Java version 1.8.0_292 ** END proof description ** Total number of generated unfolded rules = 299