/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: f(s(x),y) -> f(x,s(x)) f(x,s(y)) -> f(y,x) f(c(x),y) -> f(x,s(x)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 1 1] [1 1 0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [1 1 0] [1] [s](x0) = [1 1 1]x0 + [1] [1 1 1] [0], [1 1 1] [0] [c](x0) = [1 1 1]x0 + [1] [1 1 0] [1] orientation: [3 3 2] [1 1 0] [2] [3 3 2] [2] f(s(x),y) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0] = f(x,s(x)) [0 0 0] [0 0 0] [0] [0 0 0] [0] [1 1 1] [2 2 1] [2] [1 1 0] [1 1 1] f(x,s(y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y = f(y,x) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [3 3 2] [1 1 0] [2] [3 3 2] [2] f(c(x),y) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0] = f(x,s(x)) [0 0 0] [0 0 0] [0] [0 0 0] [0] problem: f(s(x),y) -> f(x,s(x)) f(c(x),y) -> f(x,s(x)) Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1) = 3x0 + 2x1 + 1, [s](x0) = 3x0 + 7, [c](x0) = 3x0 + 7 orientation: f(s(x),y) = 9x + 2y + 22 >= 9x + 15 = f(x,s(x)) f(c(x),y) = 9x + 2y + 22 >= 9x + 15 = f(x,s(x)) problem: Qed