/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(x1)) -> C(x1) b(c(x1)) -> A(x1) c(a(x1)) -> B(x1) A(C(x1)) -> b(x1) C(B(x1)) -> a(x1) B(A(x1)) -> c(x1) a(a(a(a(a(x1))))) -> A(A(A(x1))) A(A(A(A(x1)))) -> a(a(a(a(x1)))) b(b(b(b(b(x1))))) -> B(B(B(x1))) B(B(B(B(x1)))) -> b(b(b(b(x1)))) c(c(c(c(c(x1))))) -> C(C(C(x1))) C(C(C(C(x1)))) -> c(c(c(c(x1)))) B(a(a(a(a(x1))))) -> c(A(A(A(x1)))) A(A(A(b(x1)))) -> a(a(a(a(C(x1))))) C(b(b(b(b(x1))))) -> a(B(B(B(x1)))) B(B(B(c(x1)))) -> b(b(b(b(A(x1))))) A(c(c(c(c(x1))))) -> b(C(C(C(x1)))) C(C(C(a(x1)))) -> c(c(c(c(B(x1))))) a(A(x1)) -> x1 A(a(x1)) -> x1 b(B(x1)) -> x1 B(b(x1)) -> x1 c(C(x1)) -> x1 C(c(x1)) -> x1 Proof: Matrix Interpretation Processor: dim=1 interpretation: [A](x0) = x0 + 3, [a](x0) = x0 + 2, [c](x0) = x0 + 2, [B](x0) = x0 + 3, [b](x0) = x0 + 2, [C](x0) = x0 + 3 orientation: a(b(x1)) = x1 + 4 >= x1 + 3 = C(x1) b(c(x1)) = x1 + 4 >= x1 + 3 = A(x1) c(a(x1)) = x1 + 4 >= x1 + 3 = B(x1) A(C(x1)) = x1 + 6 >= x1 + 2 = b(x1) C(B(x1)) = x1 + 6 >= x1 + 2 = a(x1) B(A(x1)) = x1 + 6 >= x1 + 2 = c(x1) a(a(a(a(a(x1))))) = x1 + 10 >= x1 + 9 = A(A(A(x1))) A(A(A(A(x1)))) = x1 + 12 >= x1 + 8 = a(a(a(a(x1)))) b(b(b(b(b(x1))))) = x1 + 10 >= x1 + 9 = B(B(B(x1))) B(B(B(B(x1)))) = x1 + 12 >= x1 + 8 = b(b(b(b(x1)))) c(c(c(c(c(x1))))) = x1 + 10 >= x1 + 9 = C(C(C(x1))) C(C(C(C(x1)))) = x1 + 12 >= x1 + 8 = c(c(c(c(x1)))) B(a(a(a(a(x1))))) = x1 + 11 >= x1 + 11 = c(A(A(A(x1)))) A(A(A(b(x1)))) = x1 + 11 >= x1 + 11 = a(a(a(a(C(x1))))) C(b(b(b(b(x1))))) = x1 + 11 >= x1 + 11 = a(B(B(B(x1)))) B(B(B(c(x1)))) = x1 + 11 >= x1 + 11 = b(b(b(b(A(x1))))) A(c(c(c(c(x1))))) = x1 + 11 >= x1 + 11 = b(C(C(C(x1)))) C(C(C(a(x1)))) = x1 + 11 >= x1 + 11 = c(c(c(c(B(x1))))) a(A(x1)) = x1 + 5 >= x1 = x1 A(a(x1)) = x1 + 5 >= x1 = x1 b(B(x1)) = x1 + 5 >= x1 = x1 B(b(x1)) = x1 + 5 >= x1 = x1 c(C(x1)) = x1 + 5 >= x1 = x1 C(c(x1)) = x1 + 5 >= x1 = x1 problem: B(a(a(a(a(x1))))) -> c(A(A(A(x1)))) A(A(A(b(x1)))) -> a(a(a(a(C(x1))))) C(b(b(b(b(x1))))) -> a(B(B(B(x1)))) B(B(B(c(x1)))) -> b(b(b(b(A(x1))))) A(c(c(c(c(x1))))) -> b(C(C(C(x1)))) C(C(C(a(x1)))) -> c(c(c(c(B(x1))))) String Reversal Processor: a(a(a(a(B(x1))))) -> A(A(A(c(x1)))) b(A(A(A(x1)))) -> C(a(a(a(a(x1))))) b(b(b(b(C(x1))))) -> B(B(B(a(x1)))) c(B(B(B(x1)))) -> A(b(b(b(b(x1))))) c(c(c(c(A(x1))))) -> C(C(C(b(x1)))) a(C(C(C(x1)))) -> B(c(c(c(c(x1))))) Bounds Processor: bound: 0 enrichment: match automaton: final states: {22,19,14,11,6,1} transitions: A0(5) -> 1* A0(3) -> 4* A0(4) -> 5* A0(18) -> 14* f60() -> 2* b0(15) -> 16* b0(17) -> 18* b0(2) -> 15* b0(16) -> 17* B0(12) -> 13* B0(13) -> 11* B0(7) -> 12* B0(25) -> 22* c0(24) -> 25* c0(2) -> 3* c0(3) -> 23* c0(23) -> 24* a0(7) -> 8* a0(9) -> 10* a0(8) -> 9* a0(2) -> 7* C0(20) -> 21* C0(10) -> 6* C0(15) -> 20* C0(21) -> 19* 19 -> 3,23,24,25 14 -> 3* 11 -> 15,16,17,18 22 -> 7* 6 -> 15* 1 -> 7,8,9,10 problem: Qed