/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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NO

After renaming modulo the bijection { a ↦ 0, b ↦ 1 },
it remains to prove termination of the 2-rule system
{ 0 0 0 ⟶ 0 1 1 ,
  1 0 1 ⟶ 0 1 0 }

Loop of length 6 starting with a string of length 6
using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }:

.aaa.aba
	rule aaa-> abb at position 0
.abb.aba
	rule bab-> aba at position 2
.ababa.a
	rule bab-> aba at position 1
.aabaa.a
	rule aaa-> abb at position 3
.aababb.
	rule bab-> aba at position 2
.aaabab.
	rule bab-> aba at position 3
.aaaaba.