/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 },
it remains to prove termination of the 3-rule system
{ 0 1 ⟶ 1 2 0 ,
  1 2 ⟶ 2 1 1 ,
  0 2 ⟶ 2 0 1 }

The system was reversed.

After renaming modulo the bijection { 1 ↦ 0, 0 ↦ 1, 2 ↦ 2 },
it remains to prove termination of the 3-rule system
{ 0 1 ⟶ 1 2 0 ,
  2 0 ⟶ 0 0 2 ,
  2 1 ⟶ 0 1 2 }

Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols.

After renaming modulo the bijection { (0,↑) ↦ 0, (1,↓) ↦ 1, (2,↑) ↦ 2, (0,↓) ↦ 3, (2,↓) ↦ 4 },
it remains to prove termination of the 10-rule system
{ 0 1 ⟶ 2 3 ,
  0 1 ⟶ 0 ,
  2 3 ⟶ 0 3 4 ,
  2 3 ⟶ 0 4 ,
  2 3 ⟶ 2 ,
  2 1 ⟶ 0 1 4 ,
  2 1 ⟶ 2 ,
  3 1 →= 1 4 3 ,
  4 3 →= 3 3 4 ,
  4 1 →= 3 1 4 }

The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 2:

0 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

1 ↦ ⎛     ⎞
    ⎜ 1 1 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

2 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

3 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

4 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

After renaming modulo the bijection { 2 ↦ 0, 3 ↦ 1, 0 ↦ 2, 4 ↦ 3, 1 ↦ 4 },
it remains to prove termination of the 7-rule system
{ 0 1 ⟶ 2 1 3 ,
  0 1 ⟶ 2 3 ,
  0 1 ⟶ 0 ,
  0 4 ⟶ 2 4 3 ,
  1 4 →= 4 3 1 ,
  3 1 →= 1 1 3 ,
  3 4 →= 1 4 3 }

The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 2:

0 ↦ ⎛     ⎞
    ⎜ 1 1 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

1 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

2 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

3 ↦ ⎛     ⎞
    ⎜ 1 0 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

4 ↦ ⎛     ⎞
    ⎜ 1 1 ⎟
    ⎜ 0 1 ⎟
    ⎝     ⎠

After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 4 ↦ 2, 3 ↦ 3 },
it remains to prove termination of the 4-rule system
{ 0 1 ⟶ 0 ,
  1 2 →= 2 3 1 ,
  3 1 →= 1 1 3 ,
  3 2 →= 1 2 3 }

The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 3:

0 ↦ ⎛       ⎞
    ⎜ 1 0 1 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 0 0 ⎟
    ⎝       ⎠

1 ↦ ⎛       ⎞
    ⎜ 1 0 0 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 1 1 ⎟
    ⎝       ⎠

2 ↦ ⎛       ⎞
    ⎜ 1 0 0 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 0 0 ⎟
    ⎝       ⎠

3 ↦ ⎛       ⎞
    ⎜ 1 0 0 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 1 2 ⎟
    ⎝       ⎠

After renaming modulo the bijection { 1 ↦ 0, 2 ↦ 1, 3 ↦ 2 },
it remains to prove termination of the 3-rule system
{ 0 1 →= 1 2 0 ,
  2 0 →= 0 0 2 ,
  2 1 →= 0 1 2 }

The system is trivially terminating.