/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 q0(a(x1)) -> x(q1(x1))
 q1(a(x1)) -> a(q1(x1))
 q1(y(x1)) -> y(q1(x1))
 a(q1(b(x1))) -> q2(a(y(x1)))
 a(q2(a(x1))) -> q2(a(a(x1)))
 a(q2(y(x1))) -> q2(a(y(x1)))
 y(q1(b(x1))) -> q2(y(y(x1)))
 y(q2(a(x1))) -> q2(y(a(x1)))
 y(q2(y(x1))) -> q2(y(y(x1)))
 q2(x(x1)) -> x(q0(x1))
 q0(y(x1)) -> y(q3(x1))
 q3(y(x1)) -> y(q3(x1))
 q3(bl(x1)) -> bl(q4(x1))

Proof:
 KBO Processor:
  weight function:
   w0 = 1
   w(q4) = w(bl) = w(q3) = w(q2) = w(b) = w(y) = w(x) = w(q1) = w(q0) = w(a) = 1
  precedence:
   b > q1 > q3 > bl > q4 > q0 > y > a > q2 > x
  problem:
   
  Qed