/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: f(x1) -> n(c(n(a(x1)))) c(f(x1)) -> f(n(a(c(x1)))) n(a(x1)) -> c(x1) c(c(x1)) -> c(x1) n(s(x1)) -> f(s(s(x1))) n(f(x1)) -> f(n(x1)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [s](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [a](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [f](x0) = [0 1 1]x0 [0 0 0] , [1 1 1] [n](x0) = [0 1 1]x0 [0 0 0] orientation: [1 0 0] [1 0 0] f(x1) = [0 1 1]x1 >= [0 0 0]x1 = n(c(n(a(x1)))) [0 0 0] [0 0 0] [1 0 0] [1 0 0] c(f(x1)) = [0 0 0]x1 >= [0 0 0]x1 = f(n(a(c(x1)))) [0 0 0] [0 0 0] [1 0 0] [1 0 0] n(a(x1)) = [0 0 0]x1 >= [0 0 0]x1 = c(x1) [0 0 0] [0 0 0] [1 0 0] [1 0 0] c(c(x1)) = [0 0 0]x1 >= [0 0 0]x1 = c(x1) [0 0 0] [0 0 0] [1 0 0] [1] [1 0 0] [0] n(s(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = f(s(s(x1))) [0 0 0] [0] [0 0 0] [0] [1 1 1] [1 1 1] n(f(x1)) = [0 1 1]x1 >= [0 1 1]x1 = f(n(x1)) [0 0 0] [0 0 0] problem: f(x1) -> n(c(n(a(x1)))) c(f(x1)) -> f(n(a(c(x1)))) n(a(x1)) -> c(x1) c(c(x1)) -> c(x1) n(f(x1)) -> f(n(x1)) WPO Processor: algebra: Sum weight function: w0 = 0 w(f) = 1 w(c) = w(n) = w(a) = 0 status function: st(c) = st(n) = st(a) = st(f) = [0] precedence: n > c > a ~ f problem: Qed