/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(a(x1)) -> b(c(x1))
 b(b(x1)) -> c(d(x1))
 c(c(x1)) -> d(d(d(x1)))
 d(c(x1)) -> b(f(x1))
 d(d(d(x1))) -> a(c(x1))
 f(f(x1)) -> f(b(x1))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [f](x0) = x0 + 5,
   
   [c](x0) = x0 + 6,
   
   [d](x0) = x0 + 4,
   
   [a](x0) = x0 + 6,
   
   [b](x0) = x0 + 5
  orientation:
   a(a(x1)) = x1 + 12 >= x1 + 11 = b(c(x1))
   
   b(b(x1)) = x1 + 10 >= x1 + 10 = c(d(x1))
   
   c(c(x1)) = x1 + 12 >= x1 + 12 = d(d(d(x1)))
   
   d(c(x1)) = x1 + 10 >= x1 + 10 = b(f(x1))
   
   d(d(d(x1))) = x1 + 12 >= x1 + 12 = a(c(x1))
   
   f(f(x1)) = x1 + 10 >= x1 + 10 = f(b(x1))
  problem:
   b(b(x1)) -> c(d(x1))
   c(c(x1)) -> d(d(d(x1)))
   d(c(x1)) -> b(f(x1))
   d(d(d(x1))) -> a(c(x1))
   f(f(x1)) -> f(b(x1))
  WPO Processor:
   algebra: Sum
   weight function:
    w0 = 0
    w(c) = 3
    w(f) = w(b) = 2
    w(d) = 1
    w(a) = 0
   status function:
    st(f) = st(d) = st(b) = st(c) = st(a) = [0]
   precedence:
    f > d > b > c ~ a
   problem:
    
   Qed