/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { b ↦ 0, a ↦ 1 }, it remains to prove termination of the 4-rule system { 0 1 0 0 ⟶ 0 0 0 1 0 , 0 1 1 0 0 ⟶ 0 1 0 0 1 1 0 , 0 1 1 1 0 0 ⟶ 0 1 1 0 0 1 1 1 0 , 0 1 1 1 1 0 0 ⟶ 0 1 1 1 0 0 1 1 1 1 0 } The system was reversed. After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1 }, it remains to prove termination of the 4-rule system { 0 0 1 0 ⟶ 0 1 0 0 0 , 0 0 1 1 0 ⟶ 0 1 1 0 0 1 0 , 0 0 1 1 1 0 ⟶ 0 1 1 1 0 0 1 1 0 , 0 0 1 1 1 1 0 ⟶ 0 1 1 1 1 0 0 1 1 1 0 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (0,↓) ↦ 1, (1,↓) ↦ 2 }, it remains to prove termination of the 16-rule system { 0 1 2 1 ⟶ 0 2 1 1 1 , 0 1 2 1 ⟶ 0 1 1 , 0 1 2 1 ⟶ 0 1 , 0 1 2 2 1 ⟶ 0 2 2 1 1 2 1 , 0 1 2 2 1 ⟶ 0 1 2 1 , 0 1 2 2 1 ⟶ 0 2 1 , 0 1 2 2 2 1 ⟶ 0 2 2 2 1 1 2 2 1 , 0 1 2 2 2 1 ⟶ 0 1 2 2 1 , 0 1 2 2 2 1 ⟶ 0 2 2 1 , 0 1 2 2 2 2 1 ⟶ 0 2 2 2 2 1 1 2 2 2 1 , 0 1 2 2 2 2 1 ⟶ 0 1 2 2 2 1 , 0 1 2 2 2 2 1 ⟶ 0 2 2 2 1 , 1 1 2 1 →= 1 2 1 1 1 , 1 1 2 2 1 →= 1 2 2 1 1 2 1 , 1 1 2 2 2 1 →= 1 2 2 2 1 1 2 2 1 , 1 1 2 2 2 2 1 →= 1 2 2 2 2 1 1 2 2 2 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 8: 0 ↦ ⎛ ⎞ ⎜ 1 0 1 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 0 ⎟ ⎜ 0 0 1 1 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 0 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 1 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 1 0 0 0 ⎟ ⎜ 0 0 0 0 0 1 0 0 ⎟ ⎜ 0 0 0 0 0 0 1 0 ⎟ ⎜ 0 0 0 0 0 0 0 1 ⎟ ⎜ 0 0 0 0 0 0 0 0 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 13-rule system { 0 1 2 1 ⟶ 0 2 1 1 1 , 0 1 2 1 ⟶ 0 1 1 , 0 1 2 1 ⟶ 0 1 , 0 1 2 2 1 ⟶ 0 2 2 1 1 2 1 , 0 1 2 2 1 ⟶ 0 1 2 1 , 0 1 2 2 1 ⟶ 0 2 1 , 0 1 2 2 2 1 ⟶ 0 2 2 2 1 1 2 2 1 , 0 1 2 2 2 1 ⟶ 0 1 2 2 1 , 0 1 2 2 2 1 ⟶ 0 2 2 1 , 1 1 2 1 →= 1 2 1 1 1 , 1 1 2 2 1 →= 1 2 2 1 1 2 1 , 1 1 2 2 2 1 →= 1 2 2 2 1 1 2 2 1 , 1 1 2 2 2 2 1 →= 1 2 2 2 2 1 1 2 2 2 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 7: 0 ↦ ⎛ ⎞ ⎜ 1 0 1 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 ⎟ ⎜ 0 0 0 1 0 0 0 ⎟ ⎜ 0 0 0 1 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎜ 0 0 1 0 1 0 0 ⎟ ⎜ 0 0 1 0 0 1 0 ⎟ ⎜ 0 0 1 0 0 0 1 ⎟ ⎜ 0 0 0 0 0 0 0 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 10-rule system { 0 1 2 1 ⟶ 0 2 1 1 1 , 0 1 2 1 ⟶ 0 1 1 , 0 1 2 1 ⟶ 0 1 , 0 1 2 2 1 ⟶ 0 2 2 1 1 2 1 , 0 1 2 2 1 ⟶ 0 1 2 1 , 0 1 2 2 1 ⟶ 0 2 1 , 1 1 2 1 →= 1 2 1 1 1 , 1 1 2 2 1 →= 1 2 2 1 1 2 1 , 1 1 2 2 2 1 →= 1 2 2 2 1 1 2 2 1 , 1 1 2 2 2 2 1 →= 1 2 2 2 2 1 1 2 2 2 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 6: 0 ↦ ⎛ ⎞ ⎜ 1 0 1 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 ⎟ ⎜ 0 0 0 1 0 0 ⎟ ⎜ 0 0 0 1 0 0 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎜ 0 0 1 0 1 0 ⎟ ⎜ 0 0 1 0 0 1 ⎟ ⎜ 0 0 0 0 0 0 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 7-rule system { 0 1 2 1 ⟶ 0 2 1 1 1 , 0 1 2 1 ⟶ 0 1 1 , 0 1 2 1 ⟶ 0 1 , 1 1 2 1 →= 1 2 1 1 1 , 1 1 2 2 1 →= 1 2 2 1 1 2 1 , 1 1 2 2 2 1 →= 1 2 2 2 1 1 2 2 1 , 1 1 2 2 2 2 1 →= 1 2 2 2 2 1 1 2 2 2 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 ↦ ⎛ ⎞ ⎜ 1 0 1 0 0 ⎟ ⎜ 0 1 0 0 0 ⎟ ⎜ 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 ⎟ ⎜ 0 0 0 0 0 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 ⎟ ⎜ 0 0 1 1 0 ⎟ ⎜ 0 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 0 0 0 ⎟ ⎜ 0 1 0 0 0 ⎟ ⎜ 0 0 0 0 0 ⎟ ⎜ 0 0 1 0 1 ⎟ ⎜ 0 0 0 0 0 ⎟ ⎝ ⎠ After renaming modulo the bijection { 1 ↦ 0, 2 ↦ 1 }, it remains to prove termination of the 4-rule system { 0 0 1 0 →= 0 1 0 0 0 , 0 0 1 1 0 →= 0 1 1 0 0 1 0 , 0 0 1 1 1 0 →= 0 1 1 1 0 0 1 1 0 , 0 0 1 1 1 1 0 →= 0 1 1 1 1 0 0 1 1 1 0 } The system is trivially terminating.