/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { 1 ↦ 0, 4 ↦ 1, 3 ↦ 2, 2 ↦ 3, 5 ↦ 4, 0 ↦ 5 }, it remains to prove termination of the 19-rule system { 0 1 ⟶ 2 0 0 3 3 1 , 4 1 ⟶ 1 3 2 0 0 0 , 5 2 5 ⟶ 3 0 0 5 3 5 , 5 4 4 ⟶ 0 5 0 2 1 3 , 0 4 1 ⟶ 5 3 4 3 5 1 , 2 4 1 ⟶ 1 0 2 1 3 2 , 1 0 1 ⟶ 2 2 3 3 2 0 , 4 1 5 ⟶ 3 1 5 1 1 5 , 4 1 5 ⟶ 4 0 4 3 0 5 , 4 1 1 ⟶ 1 0 0 2 3 1 , 4 4 1 ⟶ 2 1 1 0 3 3 , 5 4 4 5 ⟶ 5 3 5 5 2 5 , 5 4 4 1 ⟶ 5 0 2 1 2 1 , 0 1 4 1 ⟶ 5 1 4 5 3 0 , 0 1 4 4 ⟶ 5 5 0 2 1 0 , 3 4 1 5 ⟶ 5 1 0 3 1 5 , 1 2 5 4 ⟶ 2 2 3 2 4 4 , 4 1 5 5 ⟶ 0 5 1 5 3 3 , 4 1 5 3 ⟶ 2 5 1 4 5 3 } Applying sparse untiling TRFCU(2) after reversal [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { 1 ↦ 0, 0 ↦ 1, 3 ↦ 2, 2 ↦ 3, 4 ↦ 4, 5 ↦ 5 }, it remains to prove termination of the 4-rule system { 0 1 ⟶ 2 0 0 3 3 1 , 4 2 4 ⟶ 3 0 0 4 3 4 , 1 0 1 ⟶ 2 2 3 3 2 0 , 0 1 5 5 ⟶ 4 4 0 2 1 0 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3, 4 ↦ 4 }, it remains to prove termination of the 2-rule system { 0 1 ⟶ 2 0 0 3 3 1 , 4 2 4 ⟶ 3 0 0 4 3 4 } Applying sparse untiling TRFCU(2) after reversal [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { }, it remains to prove termination of the 0-rule system { } The system is trivially terminating.