/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 619 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(x1) -> b(x1) b(b(c(x1))) -> a(c(c(c(a(b(x1)))))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b c b c c -> c c c c c c a c c c a b c b c c c b" a b c b c c -> c c c c c c a c c c a b c b c c c b by OverlapClosure OC 3"a b c b c c -> c c c c c c b b c c b c c c b by OverlapClosure OC 3"a b c b c c -> c c c c c c b b c c a c c c b by OverlapClosure OC 3"a b c b c c -> c c c c c c a b c c a c c c b by OverlapClosure OC 2"a -> b by original rule (OC 1)""b b c b c c -> c c c c c c a b c c a c c c b by OverlapClosure OC 3"b b c b c c -> c c c c c c a b c c a c c c a b by OverlapClosure OC 2"b b c b c -> c c c c c c a b c c b b by OverlapClosure OC 3"b b c b c -> c c c c c c a b c c a b by OverlapClosure OC 3"b b c b c -> c c c a c c c a b c c a b by OverlapClosure OC 3"b b c b c -> c c c b b c c c a b by OverlapClosure OC 3"b b c b c -> c c c b a c c c a b by OverlapClosure OC 2"b b c -> c c c b b by OverlapClosure OC 3"b b c -> c c c a b by OverlapClosure OC 3"b b c -> a c c c a b by original rule (OC 1)""a -> by original rule (OC 1)"""a -> b by original rule (OC 1)"""b b c -> a c c c a b by original rule (OC 1)"""a -> b by original rule (OC 1)"""b b c -> a c c c a b by original rule (OC 1)"""a -> by original rule (OC 1)"""a -> b by original rule (OC 1)"""b b c -> a c c c a b by original rule (OC 1)"""a -> by original rule (OC 1)""""a -> b by original rule (OC 1)"""a -> b by original rule (OC 1)"""b b c -> a c c c a b by original rule (OC 1)" ---------------------------------------- (2) NO