/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


NO

After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 },
it remains to prove termination of the 4-rule system
{ 0 ⟶ ,
  0 1 ⟶ 1 1 0 0 2 0 ,
  1 ⟶ ,
  2 2 ⟶ }

The system was reversed.

After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 },
it remains to prove termination of the 4-rule system
{ 0 ⟶ ,
  1 0 ⟶ 0 2 0 0 1 1 ,
  1 ⟶ ,
  2 2 ⟶ }

Loop of length 8 starting with a string of length 4
using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }:

.ba.aa
	rule ba-> acaabb at position 0
.acaabb.aa
	rule ba-> acaabb at position 5
.acaabacaabb.a
	rule a->  at position 7
.acaabacabb.a
	rule a->  at position 7
.acaabacbb.a
	rule ba-> acaabb at position 8
.acaabacbacaabb.
	rule ba-> acaabb at position 7
.acaabacacaabbcaabb.
	rule a->  at position 7
.acaabaccaabbcaabb.
	rule cc->  at position 6
.acaabaaabbcaabb.