/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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NO

After renaming modulo the bijection { a ↦ 0, b ↦ 1 },
it remains to prove termination of the 1-rule system
{ 0 0 0 0 1 ⟶ 1 1 0 0 0 0 0 }

The system was reversed.

After renaming modulo the bijection { 1 ↦ 0, 0 ↦ 1 },
it remains to prove termination of the 1-rule system
{ 0 1 1 1 1 ⟶ 1 1 1 1 1 0 0 }

Loop of length 16 starting with a string of length 21
using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }:

.abbbb.bbbbbbbbbbbbbbbb
	rule abbbb-> bbbbbaa at position 0
.bbbbbaa.bbbbbbbbbbbbbbbb
	rule abbbb-> bbbbbaa at position 6
.bbbbbabbbbbaa.bbbbbbbbbbbb
	rule abbbb-> bbbbbaa at position 12
.bbbbbabbbbbabbbbbaa.bbbbbbbb
	rule abbbb-> bbbbbaa at position 11
.bbbbbabbbbbbbbbbaabaa.bbbbbbbb
	rule abbbb-> bbbbbaa at position 20
.bbbbbabbbbbbbbbbaababbbbbaa.bbbb
	rule abbbb-> bbbbbaa at position 19
.bbbbbabbbbbbbbbbaabbbbbbaabaa.bbbb
	rule abbbb-> bbbbbaa at position 17
.bbbbbabbbbbbbbbbabbbbbaabbaabaa.bbbb
	rule abbbb-> bbbbbaa at position 16
.bbbbbabbbbbbbbbbbbbbbaabaabbaabaa.bbbb
	rule abbbb-> bbbbbaa at position 32
.bbbbbabbbbbbbbbbbbbbbaabaabbaababbbbbaa.
	rule abbbb-> bbbbbaa at position 31
.bbbbbabbbbbbbbbbbbbbbaabaabbaabbbbbbaabaa.
	rule abbbb-> bbbbbaa at position 29
.bbbbbabbbbbbbbbbbbbbbaabaabbabbbbbaabbaabaa.
	rule abbbb-> bbbbbaa at position 28
.bbbbbabbbbbbbbbbbbbbbaabaabbbbbbbaabaabbaabaa.
	rule abbbb-> bbbbbaa at position 25
.bbbbbabbbbbbbbbbbbbbbaababbbbbaabbbaabaabbaabaa.
	rule abbbb-> bbbbbaa at position 24
.bbbbbabbbbbbbbbbbbbbbaabbbbbbaabaabbbaabaabbaabaa.
	rule abbbb-> bbbbbaa at position 22
.bbbbbabbbbbbbbbbbbbbbabbbbbaabbaabaabbbaabaabbaabaa.
	rule abbbb-> bbbbbaa at position 21
.bbbbbabbbbbbbbbbbbbbbbbbbbaabaabbaabaabbbaabaabbaabaa.