/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(a(b(b(x1)))) -> b(b(c(c(a(a(x1))))))
 b(b(c(c(x1)))) -> c(c(b(b(b(b(x1))))))
 a(a(c(c(x1)))) -> c(c(a(a(b(b(x1))))))

Proof:
 String Reversal Processor:
  b(b(a(a(x1)))) -> a(a(c(c(b(b(x1))))))
  c(c(b(b(x1)))) -> b(b(b(b(c(c(x1))))))
  c(c(a(a(x1)))) -> b(b(a(a(c(c(x1))))))
  WPO Processor:
   algebra: Sum
   weight function:
    w0 = 0
    w(a) = 1
    w(c) = w(b) = 0
   status function:
    st(c) = st(a) = st(b) = [0]
   precedence:
    c > b > a
   problem:
    
   Qed