/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

After renaming modulo the bijection { b ↦ 0, a ↦ 1 },
it remains to prove termination of the 4-rule system
{ 0 0 ⟶ 0 1 0 ,
  0 0 1 0 ⟶ 0 1 0 1 1 0 0 ,
  0 1 0 ⟶ 0 1 1 0 ,
  0 1 1 0 1 0 ⟶ 0 0 }

Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols.

After renaming modulo the bijection { (0,↑) ↦ 0, (0,↓) ↦ 1, (1,↓) ↦ 2 },
it remains to prove termination of the 10-rule system
{ 0 1 ⟶ 0 2 1 ,
  0 1 2 1 ⟶ 0 2 1 2 2 1 1 ,
  0 1 2 1 ⟶ 0 2 2 1 1 ,
  0 1 2 1 ⟶ 0 1 ,
  0 2 1 ⟶ 0 2 2 1 ,
  0 2 2 1 2 1 ⟶ 0 1 ,
  1 1 →= 1 2 1 ,
  1 1 2 1 →= 1 2 1 2 2 1 1 ,
  1 2 1 →= 1 2 2 1 ,
  1 2 2 1 2 1 →= 1 1 }

The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 4:

0 ↦ ⎛         ⎞
    ⎜ 1 0 0 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎝         ⎠

1 ↦ ⎛         ⎞
    ⎜ 1 0 1 1 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎝         ⎠

2 ↦ ⎛         ⎞
    ⎜ 1 0 0 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎜ 0 0 0 1 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎝         ⎠

After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 },
it remains to prove termination of the 7-rule system
{ 0 1 ⟶ 0 2 1 ,
  0 1 2 1 ⟶ 0 2 1 2 2 1 1 ,
  0 1 2 1 ⟶ 0 2 2 1 1 ,
  0 2 1 ⟶ 0 2 2 1 ,
  1 1 →= 1 2 1 ,
  1 1 2 1 →= 1 2 1 2 2 1 1 ,
  1 2 2 1 2 1 →= 1 1 }

The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 3:

0 ↦ ⎛       ⎞
    ⎜ 1 0 1 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 0 0 ⎟
    ⎝       ⎠

1 ↦ ⎛       ⎞
    ⎜ 1 0 0 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 1 0 ⎟
    ⎝       ⎠

2 ↦ ⎛       ⎞
    ⎜ 1 0 0 ⎟
    ⎜ 0 1 0 ⎟
    ⎜ 0 0 0 ⎟
    ⎝       ⎠

After renaming modulo the bijection { 0 ↦ 0, 2 ↦ 1, 1 ↦ 2 },
it remains to prove termination of the 4-rule system
{ 0 1 2 ⟶ 0 1 1 2 ,
  2 2 →= 2 1 2 ,
  2 2 1 2 →= 2 1 2 1 1 2 2 ,
  2 1 1 2 1 2 →= 2 2 }

The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 4:

0 ↦ ⎛         ⎞
    ⎜ 1 0 1 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎝         ⎠

1 ↦ ⎛         ⎞
    ⎜ 1 0 0 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎜ 0 0 0 1 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎝         ⎠

2 ↦ ⎛         ⎞
    ⎜ 1 0 0 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎜ 0 0 0 0 ⎟
    ⎜ 0 1 0 0 ⎟
    ⎝         ⎠

After renaming modulo the bijection { 2 ↦ 0, 1 ↦ 1 },
it remains to prove termination of the 3-rule system
{ 0 0 →= 0 1 0 ,
  0 0 1 0 →= 0 1 0 1 1 0 0 ,
  0 1 1 0 1 0 →= 0 0 }

The system is trivially terminating.