/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(b(b(a(x1)))) -> a(b(a(b(x1))))
 a(a(b(a(x1)))) -> a(b(b(a(x1))))
 a(a(b(b(x1)))) -> b(b(a(a(x1))))

Proof:
 String Reversal Processor:
  a(b(b(a(x1)))) -> b(a(b(a(x1))))
  a(b(a(a(x1)))) -> a(b(b(a(x1))))
  b(b(a(a(x1)))) -> a(a(b(b(x1))))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [b](x0) = x0,
    
    [a](x0) = x0 + 8
   orientation:
    a(b(b(a(x1)))) = x1 + 16 >= x1 + 16 = b(a(b(a(x1))))
    
    a(b(a(a(x1)))) = x1 + 24 >= x1 + 16 = a(b(b(a(x1))))
    
    b(b(a(a(x1)))) = x1 + 16 >= x1 + 16 = a(a(b(b(x1))))
   problem:
    a(b(b(a(x1)))) -> b(a(b(a(x1))))
    b(b(a(a(x1)))) -> a(a(b(b(x1))))
   Matrix Interpretation Processor: dim=3
    
    interpretation:
               [1 0 0]  
     [b](x0) = [0 0 1]x0
               [0 1 0]  ,
     
               [1 1 0]     [0]
     [a](x0) = [0 1 0]x0 + [1]
               [0 1 0]     [0]
    orientation:
                      [1 2 0]     [1]    [1 2 0]     [0]                 
     a(b(b(a(x1)))) = [0 1 0]x1 + [2] >= [0 1 0]x1 + [0] = b(a(b(a(x1))))
                      [0 1 0]     [1]    [0 1 0]     [1]                 
     
                      [1 2 0]     [1]    [1 2 0]     [1]                 
     b(b(a(a(x1)))) = [0 1 0]x1 + [2] >= [0 1 0]x1 + [2] = a(a(b(b(x1))))
                      [0 1 0]     [1]    [0 1 0]     [1]                 
    problem:
     b(b(a(a(x1)))) -> a(a(b(b(x1))))
    KBO Processor:
     weight function:
      w0 = 1
      w(a) = 1
      w(b) = 0
     precedence:
      b > a
     problem:
      
     Qed