/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(b(a(a(a(a(x1)))))))) -> a(a(a(a(a(b(c(b(a(a(a(b(c(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(c(b(a(x1)))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(c(b(a(x1)))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(c(b(x))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(c(b(x))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(c(b(x))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 344, 345, 502, 503, 504, 505, 506, 507, 508, 509, 510, 511, 525, 526, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538 Node 344 is start node and node 345 is final node. Those nodes are connected through the following edges: * 344 to 502 labelled b_1(0)* 345 to 345 labelled #_1(0)* 502 to 503 labelled c_1(0)* 503 to 504 labelled b_1(0)* 504 to 505 labelled a_1(0)* 505 to 506 labelled a_1(0)* 506 to 507 labelled a_1(0)* 507 to 508 labelled b_1(0)* 508 to 509 labelled c_1(0)* 509 to 510 labelled b_1(0)* 510 to 511 labelled a_1(0)* 510 to 527 labelled b_1(1)* 511 to 525 labelled a_1(0)* 511 to 527 labelled b_1(1)* 525 to 526 labelled a_1(0)* 525 to 527 labelled b_1(1)* 526 to 345 labelled a_1(0)* 526 to 527 labelled b_1(1)* 527 to 528 labelled c_1(1)* 528 to 529 labelled b_1(1)* 529 to 530 labelled a_1(1)* 530 to 531 labelled a_1(1)* 531 to 532 labelled a_1(1)* 532 to 533 labelled b_1(1)* 533 to 534 labelled c_1(1)* 534 to 535 labelled b_1(1)* 535 to 536 labelled a_1(1)* 535 to 527 labelled b_1(1)* 536 to 537 labelled a_1(1)* 536 to 527 labelled b_1(1)* 537 to 538 labelled a_1(1)* 537 to 527 labelled b_1(1)* 538 to 345 labelled a_1(1)* 538 to 527 labelled b_1(1) ---------------------------------------- (6) YES