/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(x1)))))))) -> a(a(b(a(b(a(b(a(b(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(x1)))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(a(b(a(x1)))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(a(b(x))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(x))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(a(b(x))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 563, 564, 565, 566, 567, 568, 569, 570, 571, 572, 573, 574, 575, 576, 577, 578, 579, 580, 581, 582, 583, 584, 585, 586, 587, 588 Node 563 is start node and node 564 is final node. Those nodes are connected through the following edges: * 563 to 565 labelled b_1(0)* 564 to 564 labelled #_1(0)* 565 to 566 labelled a_1(0)* 566 to 567 labelled b_1(0)* 567 to 568 labelled a_1(0)* 568 to 569 labelled a_1(0)* 569 to 570 labelled b_1(0)* 570 to 571 labelled a_1(0)* 571 to 572 labelled b_1(0)* 572 to 573 labelled a_1(0)* 572 to 577 labelled b_1(1)* 573 to 574 labelled b_1(0)* 574 to 575 labelled a_1(0)* 574 to 577 labelled b_1(1)* 575 to 576 labelled b_1(0)* 576 to 564 labelled a_1(0)* 576 to 577 labelled b_1(1)* 577 to 578 labelled a_1(1)* 578 to 579 labelled b_1(1)* 579 to 580 labelled a_1(1)* 580 to 581 labelled a_1(1)* 581 to 582 labelled b_1(1)* 582 to 583 labelled a_1(1)* 583 to 584 labelled b_1(1)* 584 to 585 labelled a_1(1)* 584 to 577 labelled b_1(1)* 585 to 586 labelled b_1(1)* 586 to 587 labelled a_1(1)* 586 to 577 labelled b_1(1)* 587 to 588 labelled b_1(1)* 588 to 564 labelled a_1(1)* 588 to 577 labelled b_1(1) ---------------------------------------- (6) YES