/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(c(a(a(a(a(x1)))))))) -> a(a(a(a(a(b(c(c(a(a(b(c(c(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(c(c(b(a(x1)))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(c(c(b(a(x1)))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(c(c(b(x))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(c(c(b(x))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(c(c(b(x))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 7, 8, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 263, 264, 265, 266, 267, 268, 269, 270, 271, 272, 273 Node 7 is start node and node 8 is final node. Those nodes are connected through the following edges: * 7 to 45 labelled c_1(0)* 8 to 8 labelled #_1(0)* 45 to 46 labelled c_1(0)* 46 to 47 labelled b_1(0)* 47 to 48 labelled a_1(0)* 48 to 49 labelled a_1(0)* 49 to 50 labelled c_1(0)* 50 to 51 labelled c_1(0)* 51 to 52 labelled b_1(0)* 52 to 53 labelled a_1(0)* 52 to 263 labelled c_1(1)* 53 to 54 labelled a_1(0)* 53 to 263 labelled c_1(1)* 54 to 55 labelled a_1(0)* 54 to 263 labelled c_1(1)* 55 to 8 labelled a_1(0)* 55 to 263 labelled c_1(1)* 263 to 264 labelled c_1(1)* 264 to 265 labelled b_1(1)* 265 to 266 labelled a_1(1)* 266 to 267 labelled a_1(1)* 267 to 268 labelled c_1(1)* 268 to 269 labelled c_1(1)* 269 to 270 labelled b_1(1)* 270 to 271 labelled a_1(1)* 270 to 263 labelled c_1(1)* 271 to 272 labelled a_1(1)* 271 to 263 labelled c_1(1)* 272 to 273 labelled a_1(1)* 272 to 263 labelled c_1(1)* 273 to 8 labelled a_1(1)* 273 to 263 labelled c_1(1) ---------------------------------------- (6) YES