/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 2 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(a(x1))))))) -> a(a(a(a(a(a(b(a(b(a(a(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(a(x1))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(b(a(x1))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(b(x)))))) -> b(a(a(a(b(a(b(a(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(x)))))) -> b(a(a(a(b(a(b(a(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(b(x)))))) -> b(a(a(a(b(a(b(a(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 368, 369, 522, 523, 524, 525, 526, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538, 539, 540, 541, 542, 543 Node 368 is start node and node 369 is final node. Those nodes are connected through the following edges: * 368 to 522 labelled b_1(0)* 369 to 369 labelled #_1(0)* 522 to 523 labelled a_1(0)* 523 to 524 labelled a_1(0)* 524 to 525 labelled a_1(0)* 525 to 526 labelled b_1(0)* 526 to 527 labelled a_1(0)* 527 to 528 labelled b_1(0)* 528 to 529 labelled a_1(0)* 528 to 533 labelled b_1(1)* 529 to 530 labelled a_1(0)* 529 to 533 labelled b_1(1)* 530 to 531 labelled a_1(0)* 530 to 533 labelled b_1(1)* 531 to 532 labelled a_1(0)* 531 to 533 labelled b_1(1)* 532 to 369 labelled a_1(0)* 532 to 533 labelled b_1(1)* 533 to 534 labelled a_1(1)* 534 to 535 labelled a_1(1)* 535 to 536 labelled a_1(1)* 536 to 537 labelled b_1(1)* 537 to 538 labelled a_1(1)* 538 to 539 labelled b_1(1)* 539 to 540 labelled a_1(1)* 539 to 533 labelled b_1(1)* 540 to 541 labelled a_1(1)* 540 to 533 labelled b_1(1)* 541 to 542 labelled a_1(1)* 541 to 533 labelled b_1(1)* 542 to 543 labelled a_1(1)* 542 to 533 labelled b_1(1)* 543 to 369 labelled a_1(1)* 543 to 533 labelled b_1(1) ---------------------------------------- (6) YES