/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(a(a(x1)))))))) -> a(a(a(a(a(b(a(b(a(a(b(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(b(a(x1)))))))) -> b(a(b(a(a(b(a(b(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(a(b(a(x1)))))))) -> b(a(b(a(a(b(a(b(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(a(b(x))))))) -> b(a(b(a(a(b(a(b(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(b(x))))))) -> b(a(b(a(a(b(a(b(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(a(b(x))))))) -> b(a(b(a(a(b(a(b(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 7, 8, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 183, 184, 185, 186, 187, 188, 189, 190, 191, 192, 194 Node 7 is start node and node 8 is final node. Those nodes are connected through the following edges: * 7 to 21 labelled b_1(0)* 8 to 8 labelled #_1(0)* 21 to 22 labelled a_1(0)* 22 to 23 labelled b_1(0)* 23 to 24 labelled a_1(0)* 24 to 25 labelled a_1(0)* 25 to 26 labelled b_1(0)* 26 to 27 labelled a_1(0)* 27 to 28 labelled b_1(0)* 28 to 29 labelled a_1(0)* 28 to 183 labelled b_1(1)* 29 to 30 labelled a_1(0)* 29 to 183 labelled b_1(1)* 30 to 31 labelled a_1(0)* 30 to 183 labelled b_1(1)* 31 to 8 labelled a_1(0)* 31 to 183 labelled b_1(1)* 183 to 184 labelled a_1(1)* 184 to 185 labelled b_1(1)* 185 to 186 labelled a_1(1)* 186 to 187 labelled a_1(1)* 187 to 188 labelled b_1(1)* 188 to 189 labelled a_1(1)* 189 to 190 labelled b_1(1)* 190 to 191 labelled a_1(1)* 190 to 183 labelled b_1(1)* 191 to 192 labelled a_1(1)* 191 to 183 labelled b_1(1)* 192 to 194 labelled a_1(1)* 192 to 183 labelled b_1(1)* 194 to 8 labelled a_1(1)* 194 to 183 labelled b_1(1) ---------------------------------------- (6) YES