/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(b(a(b(a(x1)))))))))))) -> a(a(b(a(b(a(b(a(b(a(b(a(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(b(a(a(b(a(x1)))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(a(b(a(a(b(a(x1)))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 7, 8, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 231, 232, 233, 234, 235, 236, 237, 238, 239, 240, 241, 242 Node 7 is start node and node 8 is final node. Those nodes are connected through the following edges: * 7 to 22 labelled b_1(0)* 8 to 8 labelled #_1(0)* 22 to 23 labelled a_1(0)* 23 to 24 labelled a_1(0)* 24 to 25 labelled b_1(0)* 25 to 26 labelled a_1(0)* 25 to 231 labelled b_1(1)* 26 to 27 labelled b_1(0)* 27 to 28 labelled a_1(0)* 27 to 231 labelled b_1(1)* 28 to 29 labelled b_1(0)* 29 to 30 labelled a_1(0)* 29 to 231 labelled b_1(1)* 30 to 31 labelled b_1(0)* 31 to 32 labelled a_1(0)* 31 to 231 labelled b_1(1)* 32 to 33 labelled b_1(0)* 33 to 8 labelled a_1(0)* 33 to 231 labelled b_1(1)* 231 to 232 labelled a_1(1)* 232 to 233 labelled a_1(1)* 233 to 234 labelled b_1(1)* 234 to 235 labelled a_1(1)* 234 to 231 labelled b_1(1)* 235 to 236 labelled b_1(1)* 236 to 237 labelled a_1(1)* 236 to 231 labelled b_1(1)* 237 to 238 labelled b_1(1)* 238 to 239 labelled a_1(1)* 238 to 231 labelled b_1(1)* 239 to 240 labelled b_1(1)* 240 to 241 labelled a_1(1)* 240 to 231 labelled b_1(1)* 241 to 242 labelled b_1(1)* 242 to 8 labelled a_1(1)* 242 to 231 labelled b_1(1) ---------------------------------------- (6) YES