/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination of the given CSR could be proven: (0) CSR (1) CSRInnermostProof [EQUIVALENT, 0 ms] (2) CSR (3) CSDependencyPairsProof [EQUIVALENT, 10 ms] (4) QCSDP (5) QCSDependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QCSDP (8) QCSDPSubtermProof [EQUIVALENT, 0 ms] (9) QCSDP (10) PIsEmptyProof [EQUIVALENT, 0 ms] (11) YES (12) QCSDP (13) QCSDPSubtermProof [EQUIVALENT, 0 ms] (14) QCSDP (15) PIsEmptyProof [EQUIVALENT, 0 ms] (16) YES ---------------------------------------- (0) Obligation: Context-sensitive rewrite system: The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The replacement map contains the following entries: from: {1} cons: {1} s: {1} sel: {1, 2} 0: empty set ---------------------------------------- (1) CSRInnermostProof (EQUIVALENT) The CSR is orthogonal. By [CS_Inn] we can switch to innermost. ---------------------------------------- (2) Obligation: Context-sensitive rewrite system: The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The replacement map contains the following entries: from: {1} cons: {1} s: {1} sel: {1, 2} 0: empty set Innermost Strategy. ---------------------------------------- (3) CSDependencyPairsProof (EQUIVALENT) Using Improved CS-DPs [LPAR08] we result in the following initial Q-CSDP problem. ---------------------------------------- (4) Obligation: Q-restricted context-sensitive dependency pair problem: The symbols in {from_1, s_1, sel_2, SEL_2, FROM_1} are replacing on all positions. For all symbols f in {cons_2} we have mu(f) = {1}. The symbols in {U_1} are not replacing on any position. The ordinary context-sensitive dependency pairs DP_o are: SEL(s(X), cons(Y, Z)) -> SEL(X, Z) The collapsing dependency pairs are DP_c: SEL(s(X), cons(Y, Z)) -> Z The hidden terms of R are: from(s(x0)) Every hiding context is built from: aprove.DPFramework.CSDPProblem.QCSDPProblem$1@21b31f6c aprove.DPFramework.CSDPProblem.QCSDPProblem$1@12b5be80 Hence, the new unhiding pairs DP_u are : SEL(s(X), cons(Y, Z)) -> U(Z) U(s(x_0)) -> U(x_0) U(from(x_0)) -> U(x_0) U(from(s(x0))) -> FROM(s(x0)) The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The set Q consists of the following terms: from(x0) sel(0, cons(x0, x1)) sel(s(x0), cons(x1, x2)) ---------------------------------------- (5) QCSDependencyGraphProof (EQUIVALENT) The approximation of the Context-Sensitive Dependency Graph [LPAR08] contains 2 SCCs with 2 less nodes. ---------------------------------------- (6) Complex Obligation (AND) ---------------------------------------- (7) Obligation: Q-restricted context-sensitive dependency pair problem: The symbols in {from_1, s_1, sel_2} are replacing on all positions. For all symbols f in {cons_2} we have mu(f) = {1}. The symbols in {U_1} are not replacing on any position. The TRS P consists of the following rules: U(s(x_0)) -> U(x_0) U(from(x_0)) -> U(x_0) The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The set Q consists of the following terms: from(x0) sel(0, cons(x0, x1)) sel(s(x0), cons(x1, x2)) ---------------------------------------- (8) QCSDPSubtermProof (EQUIVALENT) We use the subterm processor [DA_EMMES]. The following pairs can be oriented strictly and are deleted. U(s(x_0)) -> U(x_0) U(from(x_0)) -> U(x_0) The remaining pairs can at least be oriented weakly. none Used ordering: Combined order from the following AFS and order. U(x1) = x1 Subterm Order ---------------------------------------- (9) Obligation: Q-restricted context-sensitive dependency pair problem: The symbols in {from_1, s_1, sel_2} are replacing on all positions. For all symbols f in {cons_2} we have mu(f) = {1}. The TRS P consists of the following rules: none The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The set Q consists of the following terms: from(x0) sel(0, cons(x0, x1)) sel(s(x0), cons(x1, x2)) ---------------------------------------- (10) PIsEmptyProof (EQUIVALENT) The TRS P is empty. Hence, there is no (P,Q,R,mu)-chain. ---------------------------------------- (11) YES ---------------------------------------- (12) Obligation: Q-restricted context-sensitive dependency pair problem: The symbols in {from_1, s_1, sel_2, SEL_2} are replacing on all positions. For all symbols f in {cons_2} we have mu(f) = {1}. The TRS P consists of the following rules: SEL(s(X), cons(Y, Z)) -> SEL(X, Z) The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The set Q consists of the following terms: from(x0) sel(0, cons(x0, x1)) sel(s(x0), cons(x1, x2)) ---------------------------------------- (13) QCSDPSubtermProof (EQUIVALENT) We use the subterm processor [DA_EMMES]. The following pairs can be oriented strictly and are deleted. SEL(s(X), cons(Y, Z)) -> SEL(X, Z) The remaining pairs can at least be oriented weakly. none Used ordering: Combined order from the following AFS and order. SEL(x1, x2) = x1 Subterm Order ---------------------------------------- (14) Obligation: Q-restricted context-sensitive dependency pair problem: The symbols in {from_1, s_1, sel_2} are replacing on all positions. For all symbols f in {cons_2} we have mu(f) = {1}. The TRS P consists of the following rules: none The TRS R consists of the following rules: from(X) -> cons(X, from(s(X))) sel(0, cons(X, Y)) -> X sel(s(X), cons(Y, Z)) -> sel(X, Z) The set Q consists of the following terms: from(x0) sel(0, cons(x0, x1)) sel(s(x0), cons(x1, x2)) ---------------------------------------- (15) PIsEmptyProof (EQUIVALENT) The TRS P is empty. Hence, there is no (P,Q,R,mu)-chain. ---------------------------------------- (16) YES