/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination of the given CSR could be proven: (0) CSR (1) CSRRRRProof [EQUIVALENT, 62 ms] (2) CSR (3) CSRRRRProof [EQUIVALENT, 0 ms] (4) CSR (5) CSRRRRProof [EQUIVALENT, 7 ms] (6) CSR (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Context-sensitive rewrite system: The TRS R consists of the following rules: f(0) -> cons(0, f(s(0))) f(s(0)) -> f(p(s(0))) p(s(0)) -> 0 The replacement map contains the following entries: f: {1} 0: empty set cons: {1} s: {1} p: {1} ---------------------------------------- (1) CSRRRRProof (EQUIVALENT) The following CSR is given: Context-sensitive rewrite system: The TRS R consists of the following rules: f(0) -> cons(0, f(s(0))) f(s(0)) -> f(p(s(0))) p(s(0)) -> 0 The replacement map contains the following entries: f: {1} 0: empty set cons: {1} s: {1} p: {1} Used ordering: Polynomial interpretation [POLO]: POL(0) = 1 POL(cons(x_1, x_2)) = 1 + x_1 POL(f(x_1)) = 1 + x_1 POL(p(x_1)) = x_1 POL(s(x_1)) = 1 + x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: p(s(0)) -> 0 ---------------------------------------- (2) Obligation: Context-sensitive rewrite system: The TRS R consists of the following rules: f(0) -> cons(0, f(s(0))) f(s(0)) -> f(p(s(0))) The replacement map contains the following entries: f: {1} 0: empty set cons: {1} s: {1} p: {1} ---------------------------------------- (3) CSRRRRProof (EQUIVALENT) The following CSR is given: Context-sensitive rewrite system: The TRS R consists of the following rules: f(0) -> cons(0, f(s(0))) f(s(0)) -> f(p(s(0))) The replacement map contains the following entries: f: {1} 0: empty set cons: {1} s: {1} p: {1} Used ordering: Polynomial interpretation [POLO]: POL(0) = 0 POL(cons(x_1, x_2)) = x_1 POL(f(x_1)) = 1 + 2*x_1 POL(p(x_1)) = 2*x_1 POL(s(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(0) -> cons(0, f(s(0))) ---------------------------------------- (4) Obligation: Context-sensitive rewrite system: The TRS R consists of the following rules: f(s(0)) -> f(p(s(0))) The replacement map contains the following entries: f: {1} 0: empty set s: {1} p: {1} ---------------------------------------- (5) CSRRRRProof (EQUIVALENT) The following CSR is given: Context-sensitive rewrite system: The TRS R consists of the following rules: f(s(0)) -> f(p(s(0))) The replacement map contains the following entries: f: {1} 0: empty set s: {1} p: {1} Used ordering: Matrix interpretation [MATRO] to (N^2, +, *, >=, >) : <<< POL(f(x_1)) = [[0]] + [[1, 1]] * x_1 >>> <<< POL(s(x_1)) = [[0], [1]] + [[1, 0], [1, 1]] * x_1 >>> <<< POL(0) = [[1], [1]] >>> <<< POL(p(x_1)) = [[0], [0]] + [[1, 0], [0, 0]] * x_1 >>> With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(s(0)) -> f(p(s(0))) ---------------------------------------- (6) Obligation: Context-sensitive rewrite system: R is empty. ---------------------------------------- (7) RisEmptyProof (EQUIVALENT) The CSR R is empty. Hence, termination is trivially proven. ---------------------------------------- (8) YES