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TRS Stand 20472 pair #381712878
details
property
value
status
complete
benchmark
list-sum-prod-bin.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n056.star.cs.uiowa.edu
space
CiME_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.77334189415 seconds
cpu usage
4.027169092
max memory
2.50380288E8
stage attributes
key
value
output-size
15043
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) MRRProof [EQUIVALENT, 0 ms] (9) QDP (10) PisEmptyProof [EQUIVALENT, 0 ms] (11) YES (12) QDP (13) MNOCProof [EQUIVALENT, 0 ms] (14) QDP (15) UsableRulesProof [EQUIVALENT, 0 ms] (16) QDP (17) QReductionProof [EQUIVALENT, 0 ms] (18) QDP (19) QDPSizeChangeProof [EQUIVALENT, 0 ms] (20) YES (21) QDP (22) UsableRulesProof [EQUIVALENT, 0 ms] (23) QDP (24) QDPSizeChangeProof [EQUIVALENT, 0 ms] (25) YES (26) QDP (27) MNOCProof [EQUIVALENT, 0 ms] (28) QDP (29) UsableRulesProof [EQUIVALENT, 0 ms] (30) QDP (31) QReductionProof [EQUIVALENT, 0 ms] (32) QDP (33) QDPSizeChangeProof [EQUIVALENT, 0 ms] (34) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(#) -> # +(x, #) -> x +(#, x) -> x +(0(x), 0(y)) -> 0(+(x, y)) +(0(x), 1(y)) -> 1(+(x, y)) +(1(x), 0(y)) -> 1(+(x, y)) +(1(x), 1(y)) -> 0(+(+(x, y), 1(#))) *(#, x) -> # *(0(x), y) -> 0(*(x, y)) *(1(x), y) -> +(0(*(x, y)), y) sum(nil) -> 0(#) sum(cons(x, l)) -> +(x, sum(l)) prod(nil) -> 1(#) prod(cons(x, l)) -> *(x, prod(l)) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: +^1(0(x), 0(y)) -> 0^1(+(x, y)) +^1(0(x), 0(y)) -> +^1(x, y) +^1(0(x), 1(y)) -> +^1(x, y) +^1(1(x), 0(y)) -> +^1(x, y) +^1(1(x), 1(y)) -> 0^1(+(+(x, y), 1(#))) +^1(1(x), 1(y)) -> +^1(+(x, y), 1(#)) +^1(1(x), 1(y)) -> +^1(x, y) *^1(0(x), y) -> 0^1(*(x, y)) *^1(0(x), y) -> *^1(x, y) *^1(1(x), y) -> +^1(0(*(x, y)), y) *^1(1(x), y) -> 0^1(*(x, y)) *^1(1(x), y) -> *^1(x, y) SUM(nil) -> 0^1(#) SUM(cons(x, l)) -> +^1(x, sum(l)) SUM(cons(x, l)) -> SUM(l)
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