details

property	value
status	complete
benchmark	324.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n084.star.cs.uiowa.edu
space	COPS

run statistics

property	value
solver	muterm 5.18
configuration	default
runtime (wallclock)	2.69314599037 seconds
cpu usage	2.407945352
max memory	2.24468992E8

stage attributes

key	value
output-size	2862
starexec-result	NO

output

/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO Problem 1: (VAR x) (RULES eq(x,x) -> eq(T,T) even(0) -> true even(s(x)) -> false | eq(odd(x),false) -> eq(T,T) even(s(x)) -> true | eq(odd(x),true) -> eq(T,T) odd(0) -> false odd(s(x)) -> false | eq(even(x),false) -> eq(T,T) odd(s(x)) -> true | eq(even(x),true) -> eq(T,T) ) Problem 1: Valid CTRS Processor: -> Rules: eq(x,x) -> eq(T,T) even(0) -> true even(s(x)) -> false | eq(odd(x),false) -> eq(T,T) even(s(x)) -> true | eq(odd(x),true) -> eq(T,T) odd(0) -> false odd(s(x)) -> false | eq(even(x),false) -> eq(T,T) odd(s(x)) -> true | eq(even(x),true) -> eq(T,T) -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: EQ(x,x) -> EQ(T,T) -> QPairs: Empty -> Rules: eq(x,x) -> eq(T,T) even(0) -> true even(s(x)) -> false | eq(odd(x),false) -> eq(T,T) even(s(x)) -> true | eq(odd(x),true) -> eq(T,T) odd(0) -> false odd(s(x)) -> false | eq(even(x),false) -> eq(T,T) odd(s(x)) -> true | eq(even(x),true) -> eq(T,T) Conditional Termination Problem 2: -> Pairs: EVEN(s(x)) -> EQ(odd(x),false) EVEN(s(x)) -> EQ(odd(x),true) EVEN(s(x)) -> ODD(x) ODD(s(x)) -> EQ(even(x),false) ODD(s(x)) -> EQ(even(x),true) ODD(s(x)) -> EVEN(x) -> QPairs: EQ(x,x) -> EQ(T,T) -> Rules: eq(x,x) -> eq(T,T) even(0) -> true even(s(x)) -> false | eq(odd(x),false) -> eq(T,T) even(s(x)) -> true | eq(odd(x),true) -> eq(T,T) odd(0) -> false odd(s(x)) -> false | eq(even(x),false) -> eq(T,T) odd(s(x)) -> true | eq(even(x),true) -> eq(T,T) Problem 1: SCC Processor: -> Pairs: EQ(x,x) -> EQ(T,T) -> QPairs: Empty -> Rules: eq(x,x) -> eq(T,T) even(0) -> true even(s(x)) -> false | eq(odd(x),false) -> eq(T,T) even(s(x)) -> true | eq(odd(x),true) -> eq(T,T) odd(0) -> false odd(s(x)) -> false | eq(even(x),false) -> eq(T,T) odd(s(x)) -> true | eq(even(x),true) -> eq(T,T) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: EQ(x,x) -> EQ(T,T) ->->-> Rules: eq(x,x) -> eq(T,T) even(0) -> true even(s(x)) -> false | eq(odd(x),false) -> eq(T,T) even(s(x)) -> true | eq(odd(x),true) -> eq(T,T) odd(0) -> false odd(s(x)) -> false | eq(even(x),false) -> eq(T,T) odd(s(x)) -> true | eq(even(x),true) -> eq(T,T) Problem 1: popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Condi 20667