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Integ Trans Syste 27634 pair #381737359
details
property
value
status
complete
benchmark
heidy7.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n092.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.11758112907 seconds
cpu usage
2.248485237
max memory
1.9755008E7
stage attributes
key
value
output-size
2542
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f6#(x1, x2, x3) -> f5#(x1, x2, x3) f5#(I0, I1, I2) -> f4#(I0, 0, I2) f4#(I3, I4, I5) -> f3#(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5] f4#(I6, I7, I8) -> f2#(I6, I7, I8) [I8 <= 0] f3#(I9, I10, I11) -> f4#(I9, I10, -1 + I11) [1 <= I9] f3#(I12, I13, I14) -> f4#(I12, I13, -2 + I14) [I12 <= 0] f2#(I15, I16, I17) -> f1#(I18, I16, I17) [I18 = I18] f1#(I19, I20, I21) -> f2#(I19, 1, I21) [1 <= I19] f1#(I22, I23, I24) -> f2#(I22, 2, I24) [I22 <= 0] R = f6(x1, x2, x3) -> f5(x1, x2, x3) f5(I0, I1, I2) -> f4(I0, 0, I2) f4(I3, I4, I5) -> f3(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5] f4(I6, I7, I8) -> f2(I6, I7, I8) [I8 <= 0] f3(I9, I10, I11) -> f4(I9, I10, -1 + I11) [1 <= I9] f3(I12, I13, I14) -> f4(I12, I13, -2 + I14) [I12 <= 0] f2(I15, I16, I17) -> f1(I18, I16, I17) [I18 = I18] f1(I19, I20, I21) -> f2(I19, 1, I21) [1 <= I19] f1(I22, I23, I24) -> f2(I22, 2, I24) [I22 <= 0] The dependency graph for this problem is: 0 -> 1 1 -> 2, 3 2 -> 4, 5 3 -> 6 4 -> 2, 3 5 -> 2, 3 6 -> 7, 8 7 -> 6 8 -> 6 Where: 0) f6#(x1, x2, x3) -> f5#(x1, x2, x3) 1) f5#(I0, I1, I2) -> f4#(I0, 0, I2) 2) f4#(I3, I4, I5) -> f3#(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5] 3) f4#(I6, I7, I8) -> f2#(I6, I7, I8) [I8 <= 0] 4) f3#(I9, I10, I11) -> f4#(I9, I10, -1 + I11) [1 <= I9] 5) f3#(I12, I13, I14) -> f4#(I12, I13, -2 + I14) [I12 <= 0] 6) f2#(I15, I16, I17) -> f1#(I18, I16, I17) [I18 = I18] 7) f1#(I19, I20, I21) -> f2#(I19, 1, I21) [1 <= I19] 8) f1#(I22, I23, I24) -> f2#(I22, 2, I24) [I22 <= 0] We have the following SCCs. { 2, 4, 5 } { 6, 7, 8 } DP problem for innermost termination. P = f2#(I15, I16, I17) -> f1#(I18, I16, I17) [I18 = I18] f1#(I19, I20, I21) -> f2#(I19, 1, I21) [1 <= I19] f1#(I22, I23, I24) -> f2#(I22, 2, I24) [I22 <= 0] R = f6(x1, x2, x3) -> f5(x1, x2, x3) f5(I0, I1, I2) -> f4(I0, 0, I2) f4(I3, I4, I5) -> f3(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5] f4(I6, I7, I8) -> f2(I6, I7, I8) [I8 <= 0] f3(I9, I10, I11) -> f4(I9, I10, -1 + I11) [1 <= I9] f3(I12, I13, I14) -> f4(I12, I13, -2 + I14) [I12 <= 0] f2(I15, I16, I17) -> f1(I18, I16, I17) [I18 = I18] f1(I19, I20, I21) -> f2(I19, 1, I21) [1 <= I19] f1(I22, I23, I24) -> f2(I22, 2, I24) [I22 <= 0]
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