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Integ Trans Syste 27634 pair #381737419
details
property
value
status
complete
benchmark
ex18.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n073.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
21.2203259468 seconds
cpu usage
22.593199229
max memory
3.393536E7
stage attributes
key
value
output-size
11421
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f11#(x1, x2, x3, x4, x5, x6) -> f10#(x1, x2, x3, x4, x5, x6) f10#(I0, I1, I2, I3, I4, I5) -> f4#(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5] f5#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9] f5#(I12, I13, I14, I15, I16, I17) -> f9#(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13] f5#(I18, I19, I20, I21, I22, I23) -> f8#(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21] f9#(I24, I25, I26, I27, I28, I29) -> f8#(I24, I25, I26, I27, I28, I29) f9#(I30, I31, I32, I33, I34, I35) -> f2#(I30, 1 + I31, I32, I33, I34, I35) f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) f8#(I42, I43, I44, I45, I46, I47) -> f7#(I42, -1 + I43, 0, I45, I46, I47) f6#(I48, I49, I50, I51, I52, I53) -> f7#(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49] f2#(I60, I61, I62, I63, I64, I65) -> f5#(I60, I61, I62, I63, I64, I65) f4#(I72, I73, I74, I75, I76, I77) -> f1#(I72, I73, I74, I75, I76, I77) [1 <= I75] f1#(I84, I85, I86, I87, I88, I89) -> f2#(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84] R = f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5] f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9] f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13] f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21] f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49] f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56] f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0] f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75] f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81] f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84] The dependency graph for this problem is: 0 -> 1 1 -> 11 2 -> 5, 6 3 -> 5, 6 4 -> 8 5 -> 8 6 -> 10 7 -> 9 8 -> 7 9 -> 7 10 -> 2, 3, 4 11 -> 12 12 -> 10 Where: 0) f11#(x1, x2, x3, x4, x5, x6) -> f10#(x1, x2, x3, x4, x5, x6) 1) f10#(I0, I1, I2, I3, I4, I5) -> f4#(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5] 2) f5#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9] 3) f5#(I12, I13, I14, I15, I16, I17) -> f9#(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13] 4) f5#(I18, I19, I20, I21, I22, I23) -> f8#(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21] 5) f9#(I24, I25, I26, I27, I28, I29) -> f8#(I24, I25, I26, I27, I28, I29) 6) f9#(I30, I31, I32, I33, I34, I35) -> f2#(I30, 1 + I31, I32, I33, I34, I35) 7) f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 8) f8#(I42, I43, I44, I45, I46, I47) -> f7#(I42, -1 + I43, 0, I45, I46, I47) 9) f6#(I48, I49, I50, I51, I52, I53) -> f7#(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49] 10) f2#(I60, I61, I62, I63, I64, I65) -> f5#(I60, I61, I62, I63, I64, I65) 11) f4#(I72, I73, I74, I75, I76, I77) -> f1#(I72, I73, I74, I75, I76, I77) [1 <= I75] 12) f1#(I84, I85, I86, I87, I88, I89) -> f2#(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84] We have the following SCCs. { 2, 3, 6, 10 } { 7, 9 } DP problem for innermost termination. P = f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) f6#(I48, I49, I50, I51, I52, I53) -> f7#(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49] R = f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5] f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9] f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13] f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21] f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49] f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56] f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0] f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75] f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81] f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84] We use the reverse value criterion with the projection function NU: NU[f6#(z1,z2,z3,z4,z5,z6)] = z2 + -1 * (1 + z3) NU[f7#(z1,z2,z3,z4,z5,z6)] = z2 + -1 * (1 + z3)
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